Relative Potancy 95% CI
Hi there, I am fitting a curve and applying a sigmoidal 4PL Rodbard model and testing parallelism. I have to determine the relative potency using the inflection points (IC50). So I calculate relative potency by dividing inflection point of the standard by the inflection point of the sample (0.6479693 / 0.6477584 = 1.0003). How would I create a 95% confidence interval for the relative potency? ...
dale_lehman
ron_horne