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Latest Discussions

• How can I parse a string in 1 column use jsl?

  I want to use jsl to split data in column "result" with delimiter "|" to new column "PIN" and "value". Kindly help, thank you in advancePlease refer my attachmentnew table 

  ducthinh279

  Discussions |

  Mar 28, 2024 9:04 PM

  2396 views | 7 replies

• Data analysis on mixture design

  Hello everyone,I've tried to create a sort of mixture design using a script.The script allows me to have 10 components (a1, a2 - b1, b2, b3, b4 - c1, c2 - d1, d2) and my mixture would consist of only:a1 or a2 or 0b1 or b2 or b3 or b4 or 0c1 and/or c2d1 or d2 or 0By selecting the steps, the script provided me with an experimental design table (which I enriched with new experiments and pure componen...

  PepinLB

  Discussions |

  Mar 28, 2024 6:44 PM

  1712 views | 6 replies

• Assign variable to table based on the contain of the table name.

  I have multiple table that are open and need to assign variable based on a contain(DC1,DC2,DC3) of the table name. If table name contain DC1 assign dt1, if it Table name contain DC2 assign dt2.... Table 1: ABC_25C_DC1_2024Table 2: ABC_25C_DC2_2024Table 3: ABC_25C_DC3_2024 Here is the command line that i was try to work with.  tablelist = Get Data Table List() << get name; If(Contains(Concat Items(...

  ConfidenceOwl94

  Discussions |

  Mar 28, 2024 10:58 AM

  1317 views | 5 replies

• Multiple imputation of ordinal data

  HiWe're doing a study regarding whole number ordinal data, answers being 0 to 4. It probably being MAR and not knowing the probability of each response, made us wonder how to do multiple imputation of this data. A post showed:go to analyze > consumer research > categorical But we're stuck...Thank you in advance! 

  CovariateFilter

  Discussions |

  Mar 28, 2024 10:00 AM

  472 views | 0 replies

• Accessing summary of fit when By argument is used

  Hi, I make a summary of fit table by using the script: Names Default To Here( 1 ); dt = Data Table("Big Class Data"); biv = dt << Bivariate( Y( :weight ), X( :height ), Fit Line(), //By(:sex), ); rpt = biv << Report; rpt["Bivariate Fit of weight By height?", "Linear Fit", "Summary of Fit",Table Box( 1 )] << Make Combined Data Table;  However, I don't understand why the same...

  gam1

  Discussions |

  Mar 28, 2024 6:58 AM

  627 views | 1 replies