cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 

Discussions

Solve problems, and share tips and tricks with other JMP users.
%3CLINGO-SUB%20id%3D%22lingo-sub-307974%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3EEffect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-307974%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3E%3CP%3EHi%20can%20someone%20help%20me%3F%3C%2FP%3E%3CP%3E%26nbsp%3B%3C%2FP%3E%3CP%3EI%20am%20running%20logistic%20regression%20with%20two%20x%20variables%20below%20shows%20my%20effect%20summary%20with%20the%20logworth.%20Now%20I%20understand%20the%20logworth%20basically%20takes%20the%20-log(p-value)%20for%20each%20x%20variable%20and%20that%20works%20for%20the%20p-value%200.00219.%20What%20i%20am%20confused%20about%20is%20the%20logworth%20of%20for%20the%20p-value%200.0000%2C%20how%20is%20it%20getting%2056.125%3F%20Moreover%20in%20other%20regression%20models%20I've%20run%20into%20different%20logworths%20for%20p-value%26nbsp%3B%20of%200.%20Can%20someone%20please%20explain%20this%20to%20me%20so%20I%20can%20move%20on%20with%20my%20life%3F%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22jMOP.PNG%22%20style%3D%22width%3A%20400px%3B%22%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22jMOP.PNG%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22jMOP.PNG%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.jmp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F26780i1759E01849E47FB5%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22jMOP.PNG%22%20alt%3D%22jMOP.PNG%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FSPAN%3E%3C%2FP%3E%3CP%3E%26nbsp%3B%3C%2FP%3E%3CP%3EThank%20you!!!%3C%2FP%3E%3CP%3E%26nbsp%3B%3C%2FP%3E%3CP%3ERachel%3C%2FP%3E%3CP%3E%26nbsp%3B%3C%2FP%3E%3CP%3E%23statistics%3C%2FP%3E%3C%2FLINGO-BODY%3E%3CLINGO-LABS%20id%3D%22lingo-labs-307974%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3E%3CLINGO-LABEL%3EConsumer%20and%20Market%20Research%3C%2FLINGO-LABEL%3E%3C%2FLINGO-LABS%3E%3CLINGO-SUB%20id%3D%22lingo-sub-472249%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ERe%3A%20Effect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-472249%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3E%3CP%3Eprobably%20you%20used%20%22e%22%20in%20calculator%20which%20is%202%2C71828.%20Try%2010%5E-57%3C%2FP%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-308039%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ERe%3A%20Effect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-308039%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3EWell%20thank%20you%2C%20I%20did%20it%20with%20a%20calculator%20and%20thats%20where%20I%20got%20the%2049%20answer.%20Thank%20you%20for%20doing%20it%20out!%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-308038%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ERe%3A%20Effect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-308038%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ELet's%20review%3A%20Log10%20(7.5e-57)%20%3D%20Log10%20(7.5)%20%2B%20Log10%20(e-57)%20%3D%20Log10%20(7.5)%20-%2057%20%3D%200.875%20-%2057%20%3D%20-56.125%3CBR%20%2F%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-308037%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ERe%3A%20Effect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-308037%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3E%3CP%3E-log10%20returns%2049.8785%3C%2FP%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-308036%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ERe%3A%20Effect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-308036%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3EAre%20you%20sure%20you%20used%20-Log10%3F%3CBR%20%2F%3EBest%2C%3CBR%20%2F%3ETS%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-307997%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ERe%3A%20Effect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-307997%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3E%3CP%3E%3CA%20href%3D%22https%3A%2F%2Fcommunity.jmp.com%2Ft5%2Fuser%2Fviewprofilepage%2Fuser-id%2F2687%22%20target%3D%22_blank%22%3E%40txnelson%3C%2FA%3E%20well%20thank%20you%20cause%20i%20didn't%20realize%20I%20could%20do%20that.%20With%20that%20being%20said%20the%20value%20is%207.5e-57%20but%20when%20I%20take%20the%20-log%20of%20that%20it%20gives%20me%20%3CSPAN%3E49.8784920133.%20So%20I'm%20closer%20but%20still%20not%20spot%20on.%26nbsp%3B%3C%2FSPAN%3E%3C%2FP%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-307995%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3ERe%3A%20Effect%20Summary%20and%20the%20Logworth%20with%20p-value%20of%200%3F%3F%3F%3F%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-307995%22%20slang%3D%22en-US%22%20mode%3D%22NONE%22%3E%3CP%3Etry%20double%20clicking%20on%20the%20p-value%20and%20change%20the%20format%20to%20show%20more%20decimal%20places%20to%20see%20what%20the%20actual%20p-value%20is.%3C%2FP%3E%3C%2FLINGO-BODY%3E
Choose Language Hide Translation Bar
rlw268
Level III

Effect Summary and the Logworth with p-value of 0????

Hi can someone help me?

 

I am running logistic regression with two x variables below shows my effect summary with the logworth. Now I understand the logworth basically takes the -log(p-value) for each x variable and that works for the p-value 0.00219. What i am confused about is the logworth of for the p-value 0.0000, how is it getting 56.125? Moreover in other regression models I've run into different logworths for p-value  of 0. Can someone please explain this to me so I can move on with my life?jMOP.PNG

 

Thank you!!!

 

Rachel

 

#statistics

3 ACCEPTED SOLUTIONS

Accepted Solutions
txnelson
Super User

Re: Effect Summary and the Logworth with p-value of 0????

try double clicking on the p-value and change the format to show more decimal places to see what the actual p-value is.

Jim

View solution in original post

Thierry_S
Super User

Re: Effect Summary and the Logworth with p-value of 0????

Are you sure you used -Log10?
Best,
TS
Thierry R. Sornasse

View solution in original post

Thierry_S
Super User

Re: Effect Summary and the Logworth with p-value of 0????

Let's review: Log10 (7.5e-57) = Log10 (7.5) + Log10 (e-57) = Log10 (7.5) - 57 = 0.875 - 57 = -56.125
Thierry R. Sornasse

View solution in original post

7 REPLIES 7
txnelson
Super User

Re: Effect Summary and the Logworth with p-value of 0????

try double clicking on the p-value and change the format to show more decimal places to see what the actual p-value is.

Jim
rlw268
Level III

Re: Effect Summary and the Logworth with p-value of 0????

@txnelson well thank you cause i didn't realize I could do that. With that being said the value is 7.5e-57 but when I take the -log of that it gives me 49.8784920133. So I'm closer but still not spot on. 

Thierry_S
Super User

Re: Effect Summary and the Logworth with p-value of 0????

Are you sure you used -Log10?
Best,
TS
Thierry R. Sornasse
rlw268
Level III

Re: Effect Summary and the Logworth with p-value of 0????

-log10 returns 49.8785

Thierry_S
Super User

Re: Effect Summary and the Logworth with p-value of 0????

Let's review: Log10 (7.5e-57) = Log10 (7.5) + Log10 (e-57) = Log10 (7.5) - 57 = 0.875 - 57 = -56.125
Thierry R. Sornasse
rlw268
Level III

Re: Effect Summary and the Logworth with p-value of 0????

Well thank you, I did it with a calculator and thats where I got the 49 answer. Thank you for doing it out!
Metin_Tueluemen
Level III

Re: Effect Summary and the Logworth with p-value of 0????

probably you used "e" in calculator which is 2,71828. Try 10^-57

Recommended Articles