@ms  Thanks for sharing this!  I checked this script against an example given on the following website thanks to a colleague of mine: https://stats.stackexchange.com/questions/103800/calculate-probability-area-under-the-overlapping-ar...
 
With the mean and sigma parameters for the first and second distributions respectively: 
"For your example, with μ1=5.28,μ2=8.45,σ1=0.91,σ2=1.36μ1=5.28,μ2=8.45,σ1=0.91,σ2=1.36, this yields: c=6.70458...c=6.70458..., and the area of the green section is: 0.158413" 
 
The .JSL script gives the exact same result for the area of the overlapped section!  
 
Names Default To Here(1);
// Define curves and calculate overlap area
mean1 =  5.28;
stdev1 = 0.91;
mean2  = 8.45; 
stdev2 = 1.36; 
N1 = Expr(Normal Density(x, mean1, stdev1));
N2 = Expr(Normal Density(x, mean2, stdev2));
ovl = Integrate(Min(N1, N2), x, ., .);
Show(ovl);
//––––––––––
// Illustration
ym = xm = (-1000 :: 1000) / 100;
For(i = 1, i <= N Col(xm), i++,
    ym[i] = Min(Normal Density(xm[i], mean1, stdev1), Normal Density(xm[i], mean2, stdev2))
);
New Window("Overlap Coefficient",
    y = Graph Box(
        Y Scale(0, 1),
        X Scale(-5, 12),
        Y Function(N1, x);
        Y Function(N2, x);
        Text({0, 0.6}, "OVL% = ", ovl*100);
        Fill Color(1);
        Polygon(xm, ym);
    )
);
