Choose Language Hide Translation Bar

## is there a way to find the area common to two different normal distribution curve using JMP?

I am trying to find the area under the common portion of two different normal distribution curve. How can I do that using JMP? Any simple way to do so?

3 REPLIES 3

## Re: is there a way to find the area common to two different normal distribution curve using JMP?

In JMP 12 there is an quite efficient Integrate() function that can be used for calculating the area confined by the minimum of the two curves.

The example below is not very useful (you'd probably want to get the parameters from the distribution platform) but may give you some ideas...

Names Default To Here(1);

// Define curves and calculate overlap area

N1 = Expr(Normal Density(x, 1, 2));

N2 = Expr(Normal Density(x, 0, 1));

ovl = Integrate(Min(N1, N2), x, ., .);

Show(ovl);

//––––––––––

// Illustration

ym = xm = (-500 :: 500) / 100;

For(i = 1, i <= N Col(xm), i++,

ym[i] = Min(Normal Density(xm[i], 1, 2), Normal Density(xm[i], 0, 1))

);

New Window("Overlap Coefficient",

y = Graph Box(

Y Scale(0, 1),

X Scale(-5, 5),

Y Function(N1, x);

Y Function(N2, x);

Text({0, 0.6}, "OVL = ", ovl);

Fill Color(1);

Polygon(xm, ym);

)

); ## Re: is there a way to find the area common to two different normal distribution curve using JMP?

@ms  Thanks for sharing this!  I checked this script against an example given on the following website thanks to a colleague of mine: https://stats.stackexchange.com/questions/103800/calculate-probability-area-under-the-overlapping-ar...

With the mean and sigma parameters for the first and second distributions respectively:

"For your example, with μ1=5.28,μ2=8.45,σ1=0.91,σ2=1.36μ1=5.28,μ2=8.45,σ1=0.91,σ2=1.36, this yields: c=6.70458...c=6.70458..., and the area of the green section is: 0.158413"

The .JSL script gives the exact same result for the area of the overlapped section!

Names Default To Here(1);

// Define curves and calculate overlap area

mean1 =  5.28;
stdev1 = 0.91;

mean2  = 8.45;
stdev2 = 1.36;

N1 = Expr(Normal Density(x, mean1, stdev1));

N2 = Expr(Normal Density(x, mean2, stdev2));

ovl = Integrate(Min(N1, N2), x, ., .);

Show(ovl);

//––––––––––

// Illustration

ym = xm = (-1000 :: 1000) / 100;

For(i = 1, i <= N Col(xm), i++,

ym[i] = Min(Normal Density(xm[i], mean1, stdev1), Normal Density(xm[i], mean2, stdev2))

);

New Window("Overlap Coefficient",

y = Graph Box(

Y Scale(0, 1),

X Scale(-5, 12),

Y Function(N1, x);

Y Function(N2, x);

Text({0, 0.6}, "OVL% = ", ovl*100);

Fill Color(1);

Polygon(xm, ym);

)

);

Highlighted Staff Joined:

Mar 21, 2013

## Re: is there a way to find the area common to two different normal distribution curve using JMP?

The graph from JMP (thanks @ms) . Nice to know there is also an analytical solution. overlap

Craige