cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 
Check out the JMP® Marketplace featured Capability Explorer add-in
Choose Language Hide Translation Bar
lukasz
Level IV

Invalid row number when accessing or evaluating of column values

Hello everybody,

after creating a new column Norm_Value I want apply formula to calculate relative values based on the position of "1" in the Base_value_norm column:

		dt << New Column( "Norm_Value",
			Numeric,
			"Continuous",
			formula(
				Eval(
					Eval Expr(
						dt:Value[(:SerialNumber << get data table) << get rows where(
							dt:Base_value_norm == 1 & dt:SerialNumber == Expr( dt:SerialNumber[Row()] )
						)] / dt:Value
					)
				)
			)
		);	

The problem is when I try to execute script I get the following error:

Invalid row number when accessing or evaluating "dt::SerialNumber[ /*###*/Row()]" , dt :: SerialNumber[/*###*/Row()].

 

But If I provide the formula manually after column is created it works as desired. What can be the reason why it is not working in script? I need to do that in script since several new columns need to be created in such a way. The data table with saved formula is attached.

Thank you and best regards

1 ACCEPTED SOLUTION

Accepted Solutions
txnelson
Super User

Re: Invalid row number when accessing or evaluating of column values

Am I missing something, or can you simplify the formula to

dt = :SerialNumber << get data table;
curSerialNumber = dt:SerialNumber;
dt:Value[dt << get rows where( dt:Base_value_norm == 1 & dt:SerialNumber == curSerialNumber )] / dt:Value;
Jim

View solution in original post

2 REPLIES 2
txnelson
Super User

Re: Invalid row number when accessing or evaluating of column values

Am I missing something, or can you simplify the formula to

dt = :SerialNumber << get data table;
curSerialNumber = dt:SerialNumber;
dt:Value[dt << get rows where( dt:Base_value_norm == 1 & dt:SerialNumber == curSerialNumber )] / dt:Value;
Jim
lukasz
Level IV

Re: Invalid row number when accessing or evaluating of column values

Hi Jim,

thank you for suggestion, works as desired.

Best regards.