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joemama985
Level III

Converting percent loss to probits in JMP

I generated independent probit regressions for multiple populations to a toxicant using a binomial general linear model with a probit link function and log(dose) as the X. Now I wish to convert my Y to probit units.

 

When I save formulae from the GLM output I get this formula for each population:

 Normal Distribution(Intercept+Slope*Log(dose))

 

Given that a probit is the inverse of the cumulative distribution function I was thinking to make a new column with the formula:

 (1) Normal Quantile(Normal Distribution(Intercept+Slope*Log(dose)))+5         *Note that the +5 is arbitrary  

 

the output above seemed reasonable to me but I was confused to have both the normal quantile in addition to the normal dist in the equation and I would think that they would cancel each other and I decided to try the formula without the normal distribution as follows:

(2) Normal Quantile(Intercept+Slope*Log(dose)))+5   

 

Once the  "normal distirbution" is removed, as in (2), It dramatically influences the shape. Moreover, you can see the the 50% lethal dose (5 probits) changes depending on the equation, which is really important

 

Capture.JPG

Dashed lines are equation(1) and solid are equation (2) for each population. 

 

Did I convert to probits correctly in equation 1?  I have done a bit of research and have not seen mention of how to do this in JMP.

 

Thanks!

 

6 REPLIES 6

Re: Converting percent loss to probits in JMP

I honestly do not know what you mean by "probit units." Here is a mock up of a simple probit analysis. I created a test with increasing dose. There are 25 subjects for each dose. The number of deaths out of 25 is recorded.

 

Screen Shot 2020-04-25 at 7.47.29 AM.png

 

Next I started the probit analysis with this set up in the Fit Model launch dialog:

 

Screen Shot 2020-04-25 at 7.48.48 AM.png

 

I then get this analysis.

 

Screen Shot 2020-04-25 at 7.51.30 AM.png

 

The plot shows the fitted probit curve as a function of Log Dose. The range of the probit function is 0 to 1. I saved the prediction formula to the data table.

 

Screen Shot 2020-04-25 at 7.53.43 AM.png

 

The prediction formula is:

 

Screen Shot 2020-04-25 at 7.54.53 AM.png

 

The predicted deaths is the sample times the probit or normal cumulative distribution function (CDF).

 

Is this quantity what you want? If not, please define "probit units" in terms of this example.

Re: Converting percent loss to probits in JMP

I forgot to add that there is an Inverse Prediction command available from the platform red triangle menu. In this example, I am asking for the Log Dose for several points from the CDF.

 

Screen Shot 2020-04-25 at 7.58.59 AM.png

 

The result is:

 

Screen Shot 2020-04-25 at 8.01.11 AM.png

 

Is this result what you are looking for?

joemama985
Level III

Re: Converting percent loss to probits in JMP

Sorry for being unclear in my initial question. I was trying to perform a probit transformation and convert the Y axis from a percentage (on the CDF of a normal distribuion: Φ(x)) into probits (the inverse of the CDF of a normal dist: Φ^-1(p)). See the snapshot from google below:

 

Capture2.JPG

 

This is  important for visualizing dose response for mortality, because the lethality of a toxicant in a population is not normally distributed (it is lognormal REF). Traditionally, toxicologists would convert percentage mortality into probits (See the 1952 Finney probit chart) prior to making a simple regression by hand, because it linearized the dose-response relationship (easier without computers). In my analysis previously mentioned, I account for this by employing the use of the probit link function. But the output is not in probits because it is predicted percent on a CDF normal dist. It is my understanding that this is the optimal way to visualize and compare dose response relationships between populations. 

 

I did manage to figure out how to transform the Y of the predicted formulae into probits for visual purposes using:

 

Normal Quantile((Normal Distribution(Intercept+Slope*Log(dose))))

 

I merely needed to add an extra set of parenthesis!! I am confident because it gives me the same median lethal dose and linearizes the line:

probit capure.JPG

In the above graph, I added .5 to the aforementioned formula because 0 probits= 50% mortality and by adding .5 they would intersect at the same median lethal dose. 

 

 You obviously know this stuff better than me, but I wanted to type it out to hopefully be of use to future users that might also want to transform the output into probits. Does this seem reasonable to you?

 

Re: Converting percent loss to probits in JMP

Many historical methods have been surpassed by superior methods when new theories, techniques, and technology become available. The older methods fade very slowly as we tend to hold on to anything that was successful in the past. Your results are correct, though, if you wish to pursue this approach.

 

I am not a toxicologist. I am a scientist, though, and a statistician. I would use the GLM as you have and include the population (e.g., Treatment) in the model. For example, let's extend my previous example:

 

Screen Shot 2020-04-25 at 1.44.44 PM.png

 

Set up the model using the Fit Model launch dialog as before and include Treatment.

 

Screen Shot 2020-04-25 at 1.49.26 PM.png

 

The Treatment effect will test an average difference (i.e., a unique intercept) indicating that one curve shifts left or right relative to the other curve. The Treatment * Log Dose effect will test a difference in the effect of Dose indicating a stronger or weaker transition between the asymptotes.

 

Screen Shot 2020-04-25 at 1.51.15 PM.png

 

The regression plot in JMP clearly shows the two curves. The Effect Tests provide statistical evidence to decide about any difference between the curves. I don't see how a transformation will make this comparison more effective.

tox
tox
Level III

Re: Converting percent loss to probits in JMP

Good afternoon Mark,

 

I know it was a while ago, but thank you for providing your reply above.  I found it very helpful. 

 

I had one follow up question for you on part of your response: 

" The Treatment * Log Dose effect will test a difference in the effect of Dose indicating a stronger or weaker transition between the asymptotes."

 

Would it be correct to say that the Treatment * Log Dose effect is essentially comparing the slopes of the dose-response curves for the two treatments? 

Re: Converting percent loss to probits in JMP

Literally, I mean that the value of the parameter for Dose in the model. It you think of that parameter as 'slope,' then yes, it is comparing the curves that way.