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view all learning resourcesIn the following table, I would like to create a column in which each "Sample" value is divided by the average of "Control" grouped by X.For examples, each "Sample" in "X1" will be divided by average of "Control" from "X1", each "Sample" in "X2" will be divided by average of "Control" from "X2".I can get the mean of "Control" by creating a formula that calculates Col Mean grouped by "X" and "Type"...
GroupSquareWolf
I have JMP 16 but and have no issues with my JMP addin query working. JMP 15 users have an error when running the below and don't get the table.
Open Database(
"DSN=PI SQL Connection Lab;Description=PI SQL Connection Lab;UID=;Trusted_Connection=Yes;APP=JMP;WSID=SFX-5GCN2M1;DATABASE=LabData",
"select t.* from (select t.*, row_number() over (partition by SiteID, TimeStamp order by (sele...
bjbreitling
Hello everybody, I've successfully run my first RS design but I struggle to understand the solution provided after fitting the model. My design includes 5 continous factors with 4 axial points and 2 center points. I did 1 replicate and fitted the model. There is no significant lack of fit. The goal is to minimized the response and but the solution is higher than all of my measured values. I includ...
FactorAlligator
I have to determine what terms appear most dominant to the response based on the parameter estimates table. I am a little confused because of the negative coefficients for some of the terms under the estimate column.
kenlynn2
I have JMP 16 but and have no issues with my JMP addin query working. JMP 15 users have an error when running the below and don't get the table.
Open Database(
"DSN=PI SQL Connection Lab;Description=PI SQL Connection Lab;UID=;Trusted_Connection=Yes;APP=JMP;WSID=SFX-5GCN2M1;DATABASE=LabData",
"select t.* from (select t.*, row_number() over (partition by SiteID, TimeStamp order by (sele...
bjbreitling
Hello everybody, I've successfully run my first RS design but I struggle to understand the solution provided after fitting the model. My design includes 5 continous factors with 4 axial points and 2 center points. I did 1 replicate and fitted the model. There is no significant lack of fit. The goal is to minimized the response and but the solution is higher than all of my measured values. I includ...
FactorAlligator
I have to determine what terms appear most dominant to the response based on the parameter estimates table. I am a little confused because of the negative coefficients for some of the terms under the estimate column.
kenlynn2
I have two computers, one with JMP Pro version 16.0 and another with Pro 16.2. Both in Windows.In JMP version 16.0, I can use Predictive Modeling>Support Vector Machines>Validation Method>KFold.With the same data sheet in JMP version 16.2, the KFold option is greyed out. I have tried many times, with many data sheets, and with many different options, but have never seen the KFold option availabl...
jkjadfasdf
Hello,I am not an expert user so please be gentle with me.I have performed PCA on some standardised data (with 2 variables) in JMP14 and noted that the two scores plots are almost mirrored across the PC1 axis. Why are they reflected in this manner? (Also, they are not perfect reflections. Why is this?)
kjwx109
Hello everyone,I am trying to make a table with the OOT (out of Trend) batches with their respective "atypical" values.I used for that the "script alarm" function as I could found some exemples on the JMP community. Here is my script: z_KSigmaZ =1.4;
// Création de la Carte de controle si N catégories > 5
Names Default To Here( 1 );
If(N Items(Associative Array(:"RNS/NS tordu (srg)")) > 5,
Gr...
Sebastienlg
I'm using JMP 16.2.0 and I'm trying to automatically generate a graph builder with box plots and their mean values with the group X variable as the color. I'm using a bar chart with style=floating to display the mean value (inspired by this topic)My current graph:This is almost what I want, except for a few things.1. I'd like the Group X variable (Recipe) to be visible in the legend as well. One w...
mvanderaa1
While taking the Exploratory Data Analysis module, it is time to practice. However, when trying to access the JMP Virtual Lab, I cannot get past the "Create User" option. JMP VIRTUAL LABTo use the Virtual Lab, please select the Create User link below. If you would prefer to use software on your own machine, please select the Download Data link below.
Create User Download Course Data Clicking the C...
TielsForTheWin
Recently switched from JMP15 for Mac to JMP16 for Mac. I was surprised to see the column switcher button removed as an option in an analysis/plot window. It used to reside up top next to the local data filter button (see black circle). The option to customize it back is also missing and has been replaced by a 'properties' button. This may also prove useful but I'm new to it. To get the colum...
datanaut
Hi,when I generate a summary table with the option "link to original data table" (selected by default), the two tables are linked:By selecting a row in the summary table the corresponding rows in the original table are selected.Cool.This also works for selections in Graphs and Dashboards.Very cool! Now my problem:After saving both tables to a project file, (precisely: after close & re-open the pro...
hogi
Jump into Graphing Date: Tuesday, September 16Time: 1:00 – 2:30 p.m. ETDuration:&nbs...
Elaborate on Elaborate: Advanced Interactive Reporting & AI-Enhanced Development In this...
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REGISTER HERE *** Note that this webinar starts at a different time than the other Fall 2025...
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