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Latest Discussions

• Intercept of a parabola

  Hi,While using JMP's "Fit Y by X" platform to fit data with a quadratic model, I observed that the intercept obtained using JMP’s centered polynomial notation for a parabola differs from the intercept obtained using the standard (uncentered) ( y = ax^2 + bx + c ) format. Based on my understanding, the intercept represents the value of ( Y ) when ( x = 0 ), and I don't see why these values should d...

  Dani

  Discussions |

  Oct 16, 2024 12:17 AM

  4075 views | 11 replies

• How can I annotate the background with different colors across different Y-axes?

  The following JSL can annotate the region of 100 to 120 on the X-axis with a different color, but it cannot span across different Y-axes. How can I modify it to annotate different variable on Y-axes with different background colors for different variables?  Names Default To Here(1); dt = Open("$SAMPLE_DATA/Big Class.jmp"); gb = dt << Graph Builder( Variables(X(:weight), Y(:height),Y(:age)), El...

  BabyDoragon

  Discussions |

  Oct 15, 2024 11:12 PM

  2100 views | 9 replies

• How does AICc criterion and Combined rules interact in Stepwise Fit Platform?

  As an entry-level user of JMP but with a bit of statistical knowledge. I encountered with a problem when trying to use the stepwise fit platform to develope a regression model for my DoE dataset. 
  
  I read the JMP help book and understand how combined rule applied to p-value based stepwise regression (a joint F-test and another partial F-test of interaction effect when added precedent main effects). ...

  Yun

  Discussions |

  Oct 15, 2024 10:52 PM

  603 views | 0 replies

• How to use a variable in JSL to set the levels of a DOE factor?

  I'm trying to add a factor to a DOE using a variable instead of hard coding the levels. The end goal is to provide the user with a simple interface set the levels for one of the factors. The following code doesn't work and the factor just ends up with L1 and L2 as levels. Names Default To Here( 1 ); levels = List(1,2,3); d = DOE( Custom Design, Add factor(Discrete Numeric, levels) ); d << Make...

  ChrisMuenzer

  Discussions |

  Oct 15, 2024 7:30 PM

  1042 views | 2 replies

• Virtual Lab will not launch

  when i try to launch virtual lab.  Instructions say that the user name and password are already filled in and not to change them.  I get an invalid username and password error when i try to continue.  

  Johnsalot

  Discussions |

  Oct 15, 2024 11:24 AM

  797 views | 2 replies