While a Control Chart has some natural features that may seem to be the direction you want to go, because it is designed to be used for Statistical Process Control as defined by Walter Shewhart, it is not a generic graphing tool, but rather, it conforms to the rules laid out to properly create a Control, i.e. Shewhart, Chart. Graph Builder, is the tool that I believe you should use.
If you only had a few columns/parameters, one could easily use JMP's interactive capabilities to produce the chart you indicated you want
That becomes very time consuming when you have the 200 parameter/columns you say you have. However, once again JMP, through JSL, has the ability to take the steps required to create the chart for one parameter/column and apply it to all of your 200 parameter/columns.
The first step towards this needs to be the calculation of the T48-T0 values. The issue here is that as described, your data has 300 parts, each with a T0 and a T48 reading. I am assuming both readings are in the same column for each measured parameter. And if this is the case, are the T0 and T48 readings found one after another, or can the T0 reading for a given part be on lets say row 1 of the data table, and then the T48 reading for that part be just somewhere else in the data table? Another question that needs to be answered is whether there are any T48 readings for a part that has a T0 reading? Both of these questions answers will help determine the easiest and most efficient way to calculate the T48-T0 difference that is needed to generate the chart you want.
If the data always has both a T0 and T48 reading for all parts, and the readings are always T0 followed immediately by the T48 reading, then all that needs to do is to go directly to Graph Builder and it can be setup to generate the desired chart. Graph Builder allows for the creation of a virtual column that a formula can be used to generate the required Difference value.
If the data are not in the correct order, or if there are missing T48 readings, additional JSL will have to be put in place to come up with the Difference value.
If you can answer those questions, and if possible could you provide a sample of your data with just a few parts and only 2 or 3 parameters I would be able to provide you with a more complete example of what you need.
Jim