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Sample size and power for two sample proportions
I need to test if a change to my line will adversely affect yields but I am not sure if I am using the correct values for Proportion 2 and the Null Difference in Proportion in the Sample Size and Power calculator for Two Sample Proportions.
I am expecting the process change to have no effect on yield but want to design a test that would have high power of detecting a 1% drop.
For Alpha=0.05 and Power=0.80, which of the options below is correct?
Option A
Proportion 1: 0.94
Proportion 2: 0.94
Null Difference in Proportion: -0.01
Option B
Proportion 1: 0.94
Proportion 2: 0.93
Null Difference in Proportion: 0
Regards
S
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Re: Sample size and power for two sample proportions
Hi swelish,
It seems as though option B is what you will want to use. Under the null hypothesis there would be no change (assuming your change to the line will have no effect on yields, the difference in the proportions will be 0). The difference between proportion 1 and 2 is what you are calculating your power to estimate -- in this case, you want high power to detect that 0.01 difference.
Option A represents a different type of test, one in which you are specifying a world in which the proportions are really the same, but under the null hypothesis one should expect that 0.01 difference. This might apply if, in the past, there has always been 0.01 difference in yields, and you want to determine power to detect that you have brought them in alignment.
I hope this helps!
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Re: Sample size and power for two sample proportions
You can read more about the two-sample proportion module here: One-Sample and Two-Sample Proportions
For more details about the computations in the power and sample size module, please see this white paper on jmp.com:
http://www.jmp.com/blind/whitepapers/wp_jmp_powersample_104887.pdf
Best,
Michael
Principal Statistical Writer
Manager, Statistical Documentation
JMP Development
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Re: Sample size and power for two sample proportions
Hi swelish,
It seems as though option B is what you will want to use. Under the null hypothesis there would be no change (assuming your change to the line will have no effect on yields, the difference in the proportions will be 0). The difference between proportion 1 and 2 is what you are calculating your power to estimate -- in this case, you want high power to detect that 0.01 difference.
Option A represents a different type of test, one in which you are specifying a world in which the proportions are really the same, but under the null hypothesis one should expect that 0.01 difference. This might apply if, in the past, there has always been 0.01 difference in yields, and you want to determine power to detect that you have brought them in alignment.
I hope this helps!
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Re: Sample size and power for two sample proportions
Thank you, Julian
That clarifies it for me.
Regards
Sean
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Re: Sample size and power for two sample proportions
You can read more about the two-sample proportion module here: One-Sample and Two-Sample Proportions
For more details about the computations in the power and sample size module, please see this white paper on jmp.com:
http://www.jmp.com/blind/whitepapers/wp_jmp_powersample_104887.pdf
Best,
Michael
Principal Statistical Writer
Manager, Statistical Documentation
JMP Development