Put in a list values of a table with condition

[#1]

I have this table :

dut  |  values

0  | 1638

1  | 618 

2  | 486

3  | 9418

0  | 654

1  | 791 

2  | 1398

3  | 4836

...

And I want put in a list, all values where the dut is 0, so have this : list = { 1638, 654 }

What syntax used ?

[#2 · Accepted solution]

My preferred method is using Data table subscripting with Loc, but there are many other ways to accomplish this

Names Default To Here(1);

dt = New Table("Untitled",
	Add Rows(8),
	New Column("dut", Numeric, "Continuous", Format("Best", 12), Set Values([0, 1, 2, 3, 0, 1, 2, 3])),
	New Column("value", Numeric, "Continuous", Format("Best", 12), Set Values([1638, 618, 486, 9418, 654, 791, 1398, 4836]))
);

zero_rows = Loc(dt[0, "dut"], 0);
list_of_values = dt[zero_rows, "value"]; // and you can convert this to list with As List();

[#3 · Accepted solution]

Here is another approach to the same solution

Names Default To Here(1);

dt = New Table("Untitled",
	Add Rows(8),
	New Column("dut", Numeric, "Continuous", Format("Best", 12), Set Values([0, 1, 2, 3, 0, 1, 2, 3])),
	New Column("value", Numeric, "Continuous", Format("Best", 12), Set Values([1638, 618, 486, 9418, 654, 791, 1398, 4836]))
);

theList = As List( :value[dt << get rows where( :dut == 0 )] );

Show( theList );

theList = as list(:value[dt<<get rows where(:dut == 0)])
/*:

{1638, 654}