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uProf
Level III

Order level based on last 3 characters of value

Hi -

 

I would like to have order of values on x axis in plot to be in ascending order. Issue is these values are alphanumeric strings and only last 3 characters are the ones that indicate order.

 

For example, I would like to see these in following order from left to right on a plot. 

 

1: YRFCA1

2: YRTCB1

3: YRACB2

4: YRTCC0

 

Row and Value order levels arranged data in a different way. 

 

I could do substring of values above and focus only on last 3 characters before ordering them but am not sure how to display entire 6 character string in the plot.

 

Appreciate input on how I could implement this in JSL.

 

Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
Craige_Hales
Super User

Re: Order level based on last 3 characters of value

5 REPLIES 5
Craige_Hales
Super User

Re: Order level based on last 3 characters of value

Maybe something like this. I created the transform column in the GUI, then saved it. Right-click the variable to transform (in the column selector), choose transform->formula. Then drag/drop the new transform variable into graph builder.

Graph Builder(
	Size( 893, 823 ),
	Show Control Panel( 0 ),
	Variables(
		X( :name ),
		Y(
			Transform Column(
				"Transform[name]",
				Character,
				Nominal,
				Formula(
					Right( :name, 3 ) || "_" || Left( :name, Length( :name ) - 3 )
				)
			)
		)
	),
	Elements( Points( X, Y, Legend( 8 ) ) )
);

Last three letters moved to front of nameLast three letters moved to front of name

Craige
ZF
ZF
Level III

Re: Order level based on last 3 characters of value

I sort the table by the last 3 character (get the substring of the last 3 char first), then set property of the long text column "value ordering" .

Names default to here(1);
dt=New Table( "order by another col",
	Add Rows( 4 ),
	New Column( "Label",
		Character,
		"Nominal",
		Set Values( {"YRFCA1", "YRTCB1", "YRACB2", "YRTCC0", "YAAAA4"} )
	),
	New Column( "Last 3",
		Character,
		"Nominal",
		Formula( Right( :Label, 3 ) ),
),
);
dt << sort(replace table(1), by(:Last 3));
values=dt:Label << get values;
dt:Label << set property ("Value Ordering", values);

value order.PNG

 

Craige_Hales
Super User

Re: Order level based on last 3 characters of value

Nice!

Craige
uProf
Level III

Re: Order level based on last 3 characters of value

Both ways are very helpful. Thanks Craige and ZF! 

jthi
Super User

Re: Order level based on last 3 characters of value

You can also "force" JMP to use ordering of non-numeric columns through JSL, but this might be a bug and not a feature so might be a bit risky to use:

 

Names Default To Here(1);
dt = New Table("table",
	Add Rows(5),
	New Column("Col", Character, "Nominal", Set Values({"YRFCA1", "YRTCB1", "YRACB2", "YRTCC0", "YAAAA4"})),
	New Column("order", Character, "Nominal", Formula(Right(:Col, 3)))
);

dt = Graph Builder(Variables(X(:Col, Order By(:order, Ascending))), Elements(Points(X, Legend(34))));

jthi_3-1629057195639.png

 

You can do it also directly from Graph builder by using two x-axis label rows:

 

jthi_0-1629056980602.png

Then if you want to you canopen x-axis settings and then do some modifications to other label's settings to hide it (in this case order):

jthi_1-1629057085369.png

and you end up with:

jthi_2-1629057094683.png

Then you could change the x-axis to remove the order /.

 

-Jarmo