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Aug 2, 2017 11:31 AM
(401 views)

Hi,

I want to show that two experimental conditions are the same using linear regression because one condition costs a lot more. When I plot x by y the Rsquared is very high (see pic). Each data point is a different sample (with expected vastly different responses), but the two conditions are the same sample measured at a different time.

However, I want to be as sure as possible when I claim that the two conditions are essentially the same to save on cost!

Is it good enough to say that the r2 is high and that means they are the same? Or should I be using some statistics from the fit x by y platform?

Any help appreciated!

2 REPLIES

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Aug 2, 2017 12:10 PM
(390 views)

R square is not specific for your purpose. For example, if you add one million to every result from one condition, you won't change R square but obviously the results are very different!

You likely want to use a *hypothesis test* to decide if the different conditions produce the same result. Unfortunately, these tests are *usually* taught and implemented to test a *difference*, not *equivalence*. In all cases, we assume that the *null hypothesis* is true unless the probability of a sample statistic at least as extreme as our result is so low that we reject the null and *accept the alternative*. So we usually assume that there is no difference, collect our sample, compute the sample statistic and its associated p-value and decide if there is a difference (in favor of the alternative).

You need to reverse the two hypotheses for your purpose: the null hypothesis is that there is a different result from the different conditions and reject that idea in favor of the alternative, which is that they are equivalent, if the p-value is sufficiently low. You actually need to use two one-sided t-tests (TOST). If you want to base it on regression, then you might consider the slope and the intercept as your sample statistics.

You must *quantitatively define* what you mean by 'equivalent.' That is, what range of values are practically equivalent. Consider the slope. A slope of 1 indicates that the linear relationship is identical. What if it is only 0.99 or 1.02? Is that difference significant to you? Let's say that you consider any slope between 0.95 and 1.05 to indicate that the linear relationship is practically the same for the rest of my reply. You must now demonstrate that the slope is *simultaneously and statistically significantly* greater than 0.95 and less than 1.05 using TOST.

JMP does not compute this result for you directly, but it comes close. The **Parameter Estimates** report provides the *estimate* and the *standard error* of the estimate. The t ratio reported here is for the hypothesis test of a difference from zero, so this statistic is **not** what you need. Set it up as TOST instead:

- Set up the upper one-tailed t-test for (estimate - 0.95) / standard error.
- Set up the lower one-tailed t-test for (estimate - 1.05) / standard error.

Both of these tests must be significant at the chosen level of significance (alpha).

You can use this script to Test for Parameter Equivalence to help, along with the written instructions, with your regression results.

Learn it once, use it forever!

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Aug 2, 2017 12:13 PM
(389 views)

Most statistical techniques are not really designed to show "equality". The idea behind hypothesis testing is to show differences. Remember that not getting a statistically significant result does not mean that you have equality (we don't accept the null hypothesis for this reason). What you need to consider is looking at "Equivalence Testing". Do a search in the JMP help to see how this approach can work. You might need to change how you are looking at the problem.

Dan Obermiller