Last column,Col Value(NCol()-1)

[#1]

I have data tables where the number of columns vary, but the last column in each table holds information such as "PASS" and "FAIL" where I want to create a new column in each table where if it is PASS then replace with numeric 1, and Fail numeric 0 with an IF statement. 

I tried

New column with formula Col Value(NCol()-1) and it does not work.   If I replace with a hard coded column value e.g., Col Value(9) it returns the pass/fail and I can use an IF statement to change to the numeric values, but I really need the NCol()-1 to paste into all the tables as the last column. 

How do I make the formula work?

IF (Col Value(NCol()-1) = "PASS", 1, 0);

[#2]

I don't really suggest doing something like this, but the formula would most likely look something like this

If(Column(N Col() - 1)[Row()] == "PASS",
	1,
	0
)

or

If(As Column(N Col() - 1) == "PASS",
	1,
	0
)

[#3]

Hi,

You have to specify a

If(  Col Value( Column( N Col() - 1 ) )== "PASS"),
	1,
	0
)

column in your formula as shown below:

[#4]

I found the solution using EVAL()

If( Col Value( Eval( N Col() - 1 ) ) == "PASS", 1, 0)

[#5]

@jthi 's approach is better documented.

Can someone explain what col value() does, or share a link to the documentation?

Wow, Eval() works?

Col Value in Formula Editor:

Hover Tip in Formula Editor: nothing

[#6]

dt = Open( "$SAMPLE_DATA/Big Class Families.jmp" );
:height << 	Set Property( "Missing Value Codes", {59} );

row()=1;
Show(col value("height")); //.
as column("height"); //.
Show(col stored value("height")); // 59

// accepts strings, columns, names ... as argument
//row=40
Show(col value("height",40));
Show(col value(:height,40));
Show(col value(5,40));
Show(col value(Column("height"),40));
Show(col value(As Column("height"),40));
As Column("height")[40];


// doesn't accept Expressions -> fix via Eval
Show(col value(2+2)); // ␀