Thank you for the answer.
It's not completely what I am looking for.
Consider this:
For( i = 0, i <= 5, i++,
For( z = 0, z < 5, z++,
if (i== 3, Break());
Print( "i=" || Char( i ) || " & z=" || Char( z ) )
);
Print ( "OUTER i = " || Char (i));
);
If I run this script, outer i is printed. The real problem here is to 'continue with the next i', without the second print-line (OUTER i = ...) will be printed. Is there an easy way to do, or do I just have to use a boolean 'continueOuterLoop'?
Thanx.
Boolean solution:
For( i = 0, i <= 5, i++,
continueOuterLoop = 0;
For( z = 0, z < 5, z++,
if (i== 3, continueOuterLoop = 1; Break(); );
Print( "i=" || Char( i ) || " & z=" || Char( z ) )
);
if (continueOuterLoop == 0,
Print ( "OUTER i = " || Char (i))
)
);