Break/Continue a (nested) outer for loop

[#1]

If I have 2 nested for-loops, how can I break/continue the outer loop?

example:

for (i=0, i<10, i++,

     for (j=0, j<10, j++,

          // Do stuff

         if ( <condition>,

               // Continue with the next i

          ); // end if

    ); // end inner loop

     // Do some more stuff

); // end outer loop

[#2 · Accepted solution]

hi Jan,

try to use the Break(). the following script will stop running when i will reach 3.

For( i = 0, i <= 5, i++,

    For( z = 0, z < 5, z++,

    if (i >= 3, Break());

        Print( "i=" || Char( i ) || " & z=" || Char( z ) )

    )

);

the next script will just skip i=3 and continue to i=4 and i=5.

For( i = 0, i <= 5, i++,

    For( z = 0, z < 5, z++,

    if (i== 3, Break());

        Print( "i=" || Char( i ) || " & z=" || Char( z ) )

    )

);

please take a look at this link for the explanation about the use Break and while:

Iterate

ron

[#3]

Thank you for the answer.

It's not completely what I am looking for.

Consider this:

For( i = 0, i <= 5, i++,

    For( z = 0, z < 5, z++,

    if (i== 3, Break());

        Print( "i=" || Char( i ) || " & z=" || Char( z ) )

    );

    Print ( "OUTER i = " || Char (i));

);

If I run this script, outer i is printed.  The real problem here is to 'continue with the next i', without the second print-line (OUTER i = ...) will be printed.  Is there an easy way to do, or do I just have to use a boolean 'continueOuterLoop'?

Thanx.

Boolean solution:

For( i = 0, i <= 5, i++,

    continueOuterLoop = 0;

    For( z = 0, z < 5, z++,

    if (i== 3, continueOuterLoop = 1; Break(); );

        Print( "i=" || Char( i ) || " & z=" || Char( z ) )

    );

    if (continueOuterLoop == 0,

        Print ( "OUTER i = " || Char (i))

        )

);