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DanAlexander
Level III

Adding x number of days to a Character Date column (dd-Mon-YYYY)

I have a JSL script that periodically pulls data from an Access database. 

 

The access database contains a date column "Available Date" with a dd-Mon-YYYY (E.g., 12-APR-2018) format. What I am trying to do, is create a new column "Target Date" in JMP that adds x number of days to the date in "Available Date" for each row.

 

For example: In the image below, the Target date is equal to Available date + 4 days. I am trying to automatically calculate the Target date based on the Available date. The number of days is based on the "Time (Months)" column.

DanAlexander_1-1616079327448.png

 

This is what I've tried so far, which obviously does not work. I think I need to convert the "Available Date" column to a numeric data type, then add the number of days & convert back to Character? 

dt << New Column("Target Date", "Character", "Nominal");

dt << For Each Row(
	IF (:"Time (Months)" <= 3, :"Target Date" = :"Available Date" + 4 ),
	IF (:"Time (Months)" > 3, :"Target Date" = :"Available Date" + 7 )
);
1 ACCEPTED SOLUTION

Accepted Solutions
txnelson
Super User

Re: Adding x number of days to a Character Date column (dd-Mon-YYYY)

Unless there is a real reason to keep the Target Date values as a character column, I suggest you convert it to a JMP Date column.

Names Default To Here( 1 );
dt = Current Data Table();

dt << new column( "Target Date", format( "ddmonyyyy") );

for each row(
	if( :"Time (Months)"n <= 3,
		:Target Date = 
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
		:Target Date = 
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 )
	)
);

d1.PNG

It is very easy to convert the above output to character by the below modification

Names Default To Here( 1 );
dt = Current Data Table();

dt << new column( "Target Date", character );

for each row(
	if( :"Time (Months)"n <= 3,
		:Target Date = format(
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
			"ddmonyyyy"
		),
		:Target Date = format(
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 ),
			"ddmonyyyy"
		)
	)
);

d2.PNG

If the output format needs to be exactly as the input data format is, the following will get that accomplished

Names Default To Here( 1 );
dt = Current Data Table();

dt << new column( "Target Date", character );

monthList = {"JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP",
"OCT", "NOV", "DEC"};
for each row(
	if( :"Time (Months)"n <= 3,
		temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
		temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 )
	);
	:Target Date = Substr( "0", Length( Char( Day( temp ) ) ) ) ||
	Char( Day( temp ) ) || "-" || monthList[Month( temp )] || "-" ||
	Char( Year( temp ) );
);

d3.PNG

If you wanted to use a formula rather than the For Each Row, this would be for formula for the above output

monthList = {"JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"};
If( :"Time (Months)"n <= 3,
	temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
	temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 )
);
Substr( "0", Length( Char( Day( temp ) ) ) ) || Char( Day( temp ) ) || "-" || monthList[Month( temp )] || "-" ||
Char( Year( temp ) );
Jim

View solution in original post

3 REPLIES 3
dale_lehman
Level VII

Re: Adding x number of days to a Character Date column (dd-Mon-YYYY)

The attached table adds 4 days to your available date column to get the target date.  Steps:  change the data type for available date to numeric/continuous with appropriate date formatting; then use the Date Increment function to add 4 days to the available date, finally change the formatting for the resulting target date column to match what you used in the available date column.

 

One additional note - in your example, it looks like you added a week (7 days rather than 4).

txnelson
Super User

Re: Adding x number of days to a Character Date column (dd-Mon-YYYY)

Unless there is a real reason to keep the Target Date values as a character column, I suggest you convert it to a JMP Date column.

Names Default To Here( 1 );
dt = Current Data Table();

dt << new column( "Target Date", format( "ddmonyyyy") );

for each row(
	if( :"Time (Months)"n <= 3,
		:Target Date = 
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
		:Target Date = 
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 )
	)
);

d1.PNG

It is very easy to convert the above output to character by the below modification

Names Default To Here( 1 );
dt = Current Data Table();

dt << new column( "Target Date", character );

for each row(
	if( :"Time (Months)"n <= 3,
		:Target Date = format(
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
			"ddmonyyyy"
		),
		:Target Date = format(
			Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 ),
			"ddmonyyyy"
		)
	)
);

d2.PNG

If the output format needs to be exactly as the input data format is, the following will get that accomplished

Names Default To Here( 1 );
dt = Current Data Table();

dt << new column( "Target Date", character );

monthList = {"JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP",
"OCT", "NOV", "DEC"};
for each row(
	if( :"Time (Months)"n <= 3,
		temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
		temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 )
	);
	:Target Date = Substr( "0", Length( Char( Day( temp ) ) ) ) ||
	Char( Day( temp ) ) || "-" || monthList[Month( temp )] || "-" ||
	Char( Year( temp ) );
);

d3.PNG

If you wanted to use a formula rather than the For Each Row, this would be for formula for the above output

monthList = {"JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"};
If( :"Time (Months)"n <= 3,
	temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 4 ),
	temp = Informat( :Available Date, "ddmonyyyy" ) + In Days( 7 )
);
Substr( "0", Length( Char( Day( temp ) ) ) ) || Char( Day( temp ) ) || "-" || monthList[Month( temp )] || "-" ||
Char( Year( temp ) );
Jim
DanAlexander
Level III

Re: Adding x number of days to a Character Date column (dd-Mon-YYYY)

This is excellent, exactly what I was trying to do - and so simple! Thank you for the help. I will leave it in the date format.

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