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Apr 29, 2019 11:18 AM
(2094 views)

Hi - i am making mulitple histogram graphs with 9 categorical levels possible - i would like all 9 levels to show on the axis, even if the frequency count is zero for a specific bin on a specific histogram... Is there a way to force zero counts to show on the graph axis (for example, the bin in included on the axis, but there is no bar since count = 0)? I think having all levels on each graph will make it easier for the reader to compare across graphs. right now i have tried using the distribution icon, but each histogram it creates has a different assortment of categorical levels. I am using JMP 13.2.1

thanks in advance for any ideas

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I assume you are using Graph Builder. There may be better ways to do this, but this should work.

I would recommend using the Value Ordering property so that each graph will have the same order on the x-axis.

Then add a column of all 1's to the table, call this column Freq. use a pre-selected role of Frequency for this column.

Now whenever you have a graph where a level is missing, add the level, but put a 0 in the Freq column. This should make it appear on the graph.

I have included a sample file with an example where level D is missing.

Dan Obermiller

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I assume you are using Graph Builder. There may be better ways to do this, but this should work.

I would recommend using the Value Ordering property so that each graph will have the same order on the x-axis.

Then add a column of all 1's to the table, call this column Freq. use a pre-selected role of Frequency for this column.

Now whenever you have a graph where a level is missing, add the level, but put a 0 in the Freq column. This should make it appear on the graph.

I have included a sample file with an example where level D is missing.

Dan Obermiller

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Re: force all histogram levels on bar graph, even if count = 0?

thank you! your advice did the trick!