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Apr 29, 2014 7:11 AM
(9431 views)

can we color the cells in jmp table as we do in excel? I mean really give colors to the part of table/cells interested?

I tried below jsl but it only works when you plot the data in graphs but not in the table itself?

Thanks in advance!

Evan

dt=Data Table( "Bin Wafer Map" );

For(i=4, i<=N col(dt),i++,

dt:i << Set Property(

"Value Colors",

{1=Green,3 = Red, 4 = Yellow,5=orange, 6 = Magenta, 7 =Blue,8 = Cyan,9=BlueCyan}

));

1 ACCEPTED SOLUTION

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In JMP 9 and beyond try right clicking on a cell in a data table and you'll get a menu that will let you color the cell.

In JSL you can use the Color Cell() message:

dt = Open

("$SAMPLE_DATA/Big Class.jmp");column

(dt, “Age”)<<Color Cells({5,{15}});

or the Color Cell by Value() message:

dt = Open

("$SAMPLE_DATA/Big Class.jmp");:Age <<

Set Property

("Value Colors",

{12= -13977430,13= -3780930,14= -

4157407,15= -13596965,16= -2210961,17= -

10562523}

);Wait

(1);:Age <<

Color Cell by Value(1);

-Jeff

-Jeff

12 REPLIES

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In JMP 9 and beyond try right clicking on a cell in a data table and you'll get a menu that will let you color the cell.

In JSL you can use the Color Cell() message:

dt = Open

("$SAMPLE_DATA/Big Class.jmp");column

(dt, “Age”)<<Color Cells({5,{15}});

or the Color Cell by Value() message:

dt = Open

("$SAMPLE_DATA/Big Class.jmp");:Age <<

Set Property

("Value Colors",

{12= -13977430,13= -3780930,14= -

4157407,15= -13596965,16= -2210961,17= -

10562523}

);Wait

(1);:Age <<

Color Cell by Value(1);

-Jeff

-Jeff

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Apr 29, 2014 1:31 PM
(8581 views)
| Posted in reply to message from Jeff_Perkinson 04/29/2014 10:28 AM

You can apply a value gradient using JSL in the following manner. Note that to use dynamically calculated values of min, max and average I had to build a string and execute it with eval(parse()).

dt = Open**(** "$SAMPLE_DATA/Big Class.jmp" **)**;

dtcol = column**(**dt, "weight"**)**;

one_min = col min**(**dtcol**)**;

one_max = col max**(**dtcol**)**;

one_avg = col mean**(**dtcol**)**;

gradient_expr = evalinsert**(**"\[

dtcol << Set Property( "Color Gradient",

{"Jet", Range(^one_min^, ^one_max^, ^one_avg^)});

dtcol << color cell by value(1);

]\"**)**;

eval**(**parse**(**gradient_expr**))**;

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Re: can we color the cells in jmp table as we do in excel? I mean really give colors to the part of

Jun 27, 2017 11:33 AM
(7295 views)
| Posted in reply to message from Jeff_Perkinson 04/29/2014 10:28 AM

Hi is there a way to color selected cells? I have a hew hundred cells that are selected and I would like to give a color to stand out.

Thanks

Sam

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Re: can we color the cells in jmp table as we do in excel? I mean really give colors to the part of

For a JMP table the selection color is controlled by the Windows selection color. Here's how to do it under windows 7: https://answers.microsoft.com/en-us/windows/forum/windows_7-desktop/how-to-change-windows-7-highligh...

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thanks Jeff and PMroz.

I got the hint and was able to get my wafer map colored by Bin(value). I did not know the color by cell value is off by default. Have not figure out how to tell jmp do nothing if the cell value is empty.

=Data Table**(** "Bin Wafer Map" **)**;

For**(**i=**4**, i<=N col**(**dt**)**,i++,

:i << **Set Property(**

"Value Colors",

**1**=Green,**3** = Red, **4** = Yellow,**5**=orange, **6** = Magenta, **7** =Blue

,**8** = Cyan,**9**=BlueCyan,**.**=white**}**

<<**color cell by value****(1))**;

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finally I got it to color only non-empty cells with desired colors. but there is still an error though the script is executable.

=Data Table**(** "Bin Wafer Map" **)**;

**(**i=**4**, i<=N col**(**dt**)**,i++,

**(**j=**1**, j<=N Row**(**dt**)**,j++,

if**(**dt:i**[**j**]**==**1**,dt:i << **Color Cells(**Green,**{**j**})**,

if**(**dt:i**[**j**]**==**3**,dt:i << **Color Cells(**Red,**{**j**})**,

if**(**dt:i**[**j**]**==**4**,dt:i << **Color Cells(**Yellow,**{**j**})**,

if**(**dt:i**[**j**]**==**5**,dt:i << **Color Cells(**Orange,**{**j**})**,

if**(**dt:i**[**j**]**==**6**,dt:i << **Color Cells(**Magenta,**{**j**})**,

if**(**dt:i**[**j**]**==**7**,dt:i << **Color Cells(**Blue,**{**j**})**,

if**(**dt:i**[**j**]**==**8**,dt:i << **Color Cells(**Cyan,**{**j**})**,

if**(**dt:i**[**j**]**==**9**,dt:i << **Color Cells(**BlueCyan,**{**j**})**,

))))));

**(**i=**4**, i<=N col**(**dt**)**,i++,

**(**j=**1**, j<=N Row**(**dt**)**,j++,

**(**!zero or missing**(**dt:i**[**j**])**,dt:i**[**j**]**<<**color cell by value****(1)**,

)));

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This code is a bit simpler. Note that I'm using k for a looping variable instead of **j**; **j** is a function in JSL.

color_list = **{**"Green", "Red", "Yellow", "Purple", "Orange", "Magenta", "Blue", "Cyan", "BlueCyan"**}**;

dt = Data Table**(** "Bin Wafer Map" **)**;

For**(** i = **4**, i <= N Col**(** dt **)**, i++,

For**(** k = **1**, k <= N Row**(** dt **)**, k++,

one_value = dt:i**[**k**]**;

if **(**! is missing**(**one_value**)**,

dt:i << color cells**(**color_list**[**one_value**]**, **{**k**})**;

dt:i << color cell by value**(** **1** **)**;

** )**;

** )**;

**)**;

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thanks, P!

your script is much simpler but it is not able to exclude the empty cells(showing X)

my script trying to send color cell by value to a cell, which works but giving below error. Do you know what the error tells us and how to debug it?

PS: I tried use below script to add a empty row btw each wafer but it might calls a infinite loop:(, never worked.

For(a=0, a<(N Row(dt))/11,a++,

dt<<add rows(1,(a+(a+1)*11));

);

Thanks a gain.

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My code excludes the empty cells with the ! is missing() check. I only get the X's for empty cells when I use a Value Gradient.

Your code is failing because that method expects a column, not a cell. Again I strongly recommend that you change j to k or something because j is a function in JSL.

I realized that the color cell by value method only needs to be called once per column, so I took it out of the k loop.

color_list = **{**"Green", "Red", "Yellow", "Purple", "Orange", "Magenta", "Blue", "Cyan", "BlueCyan"**}**;

dt = Data Table**(** "Bin Wafer Map" **)**;

For**(** i = **4**, i <= N Col**(** dt **)**, i++,

dt:i << color cell by value**(** **1** **)**;

For**(** k =**1**, k <=N Row**(** dt **)**, k++,

one_value = dt:i**[**k**]**;

if **(**! is missing**(**one_value**)**,

dt:i << color cells**(**color_list**[**one_value**]**, **{**k**})**;

** )**;

** )**;

**)**;