cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 
  • DownloadSemiconductor Toolkit: Tools to create wafer maps, add wafer geometry to graphics, explore die defects & compare wafers.
  • Discovery Summit 2026: Early User Edition - September 23-24.Register. It's free.
  • See how to design an experiment, explore factor-response relationships, assess tradeoffs, and ID best settings. Register for Sep. 11 Mastering JMP.

Discussions

Solve problems, and share tips and tricks with other JMP users.
Choose Language Hide Translation Bar
Jackie_
Level VII

Use Xpath to delete outlier box from the window

Hi,

 

I want to delete the Tabulate Outlier box upon unchecking the checkbox. I tried Xpath but something is not correct. Any suggestion?

Here is the jsl code

Names Default To Here( 1 );

dt = Open( "$SAMPLE_DATA/Semiconductor Capability.jmp" );

List1 = {"NPN1", "PNP1", "PNP2", "NPN2", "PNP3", "IVP1"};
List2 = {"PNP4", "NPN3", "IVP2", "NPN4", "SIT1"};
List3 = {"INM1", "INM2", "VPM1", "VPM2", "VPM3"};
List4 = {"SNM1", "SPM1", "NPN5", "EP2", "ZD6"};

var expr1 = Expr( Variables() );
For( c = 1, c <= N Items( List1 ), c++,
	x expr1 = Expr(
		X( Position( 1 ), Combine( "Parallel Merged" ) )
	);
	Insert Into( x expr1, List1[c], 1 );
	Insert Into( var expr1, Name Expr( x expr1 ) );
);

var expr2 = Expr( Variables() );
For( c = 1, c <= N Items( List2 ), c++,
	x expr2 = Expr(
		X( Position( 1 ), Combine( "Parallel Merged" ) )
	);
	Insert Into( x expr2, List2[c], 1 );
	Insert Into( var expr2, Name Expr( x expr2 ) );
);

var expr3 = Expr( Variables() );
For( c = 1, c <= N Items( List3 ), c++,
	x expr3 = Expr(
		X( Position( 1 ), Combine( "Parallel Merged" ) )
	);
	Insert Into( x expr3, List3[c], 1 );
	Insert Into( var expr3, Name Expr( x expr3 ) );
);

var expr4 = Expr( Variables() );
For( c = 1, c <= N Items( List4 ), c++,
	x expr4 = Expr(
		X( Position( 1 ), Combine( "Parallel Merged" ) )
	);
	Insert Into( x expr4, List4[c], 1 );
	Insert Into( var expr4, Name Expr( x expr4 ) );
);


lists = {"List1", "List2", "List3", "List4"};
var = {};
gbv = {};

For( i = 1, i <= 4, i++,
	Insert Into( var, Name Expr( Eval( Parse( "var expr" || Char( i ) ) ) ) );
	Insert Into( gbv, Parse( "vvv" || Char( i ) ) );
);

nw = New Window( "Plots",
	Show Menu( 0 ),
	show toolbars( 0 ),
	H List Box(

		Check Box(
			{"Summary"}, 
						
			<<Set Function(
				Function( {self}, 
							
					sel = self << get selected();
					If( N Items( sel ) > 0,
						For( i = 1, i <= N Items( lists ), i++,
							If( N Items( Eval( Parse( lists[i] ) ) ) > 0,
								nw[lists[i], Outline Box( 1 )] << append(
										 
					
									V Scroll Box(
										size( 580 ),
										Border Box( Left( 5 ), Right( 5 ), Top( 5 ), Bottom( 5 ), Sides( 15 ),
											Tabulate(
												Show Control Panel( 0 ),
												Set Format( Uniform Format( 10, 2 ) ),
												Add Table(
													Column Table( Statistics( Mean, Std Dev ) ),
													Row Table(
														Analysis Columns(
															Eval( Parse( lists[i] ) )
								
														)
													)
												), 
						
						
						
												SendToReport(
													Dispatch( {}, "Tabulate", OutlineBox, {Set Title( "Summary Stats" )} )
	
					
												)
											)
										)
									)
											
											
										
										
									
								) << Visibility( "Visible" );
			
							)
						);
								
					,
					/// Xpath syntax

	nw << XPath( "//Outlinebox[@helpKey = 'Summary Stats']" ) << delete;
							
								
								
								
								
					);
				);
						
			)
	
	
	
		),
		V List Box( tb = Tab Box() )
	)
);

For( i = 1, i <= N Items( lists ), i++,
	tb << Add(
		lists[i],
		V List Box(
			H List Box(
				Eval(
					Eval Expr(
						gb = dt << Graph Builder(
							Size( 1117, 781 ),
							Show Control Panel( 0 ), 
						
							Expr( Name Expr( var[i] ) ),
							Elements(
								Histogram(
									X( 1 ),
									X( 2 ),
									X( 3 ),
									X( 4 ),
									X( 5 ),
									X( 6 ),
									X( 7 ),
									X( 8 ),
									X( 9 ),
									X( 10 ),
									X( 11 ),
									X( 12 ),
									X( 13 ),
									X( 14 ),
									X( 15 ),
									X( 16 ), 
									
									Legend( 2 ), 
							
								),
								Box Plot(
									X( 1 ),
									X( 2 ),
									X( 3 ),
									X( 4 ),
									X( 5 ),
									X( 6 ),
									X( 7 ),
									X( 8 ),
									X( 9 ),
									X( 10 ),
									X( 11 ),
									X( 12 ),
									X( 13 ),
									X( 14 ),
									X( 15 ),
									X( 16 ), 
									
									Legend( 3 ),
									Outliers( 0 )
								)
							)
						)
					)
				),
				sumsta = Outline Box( 
					
					lists[i],
					<<visibility( "Collapse" )
						
						
				)
					
				
			)
		)
	);

				
	
	
	
);

 

1 ACCEPTED SOLUTION

Accepted Solutions
hogi
Level XIII

Re: Use Xpath to delete outlier box from the window

Instead of

nw << XPath( "//Outlinebox[@helpKey = 'Summary Stats']" ) << delete;

please try

(nw << XPath( "//OutlineBox[text() = 'Summary Stats']" )) << delete;

- the brackets guarantee that the delete message is sent to the Outline Box.

- use OutlineBox instead of Outlinebox (one of the few cases where Jmp is case sensitive)

- text() = ... searches for the correct title


But perhaps

(nw << XPath( "//ScrollBox" )) << delete;

is what you want :)

View solution in original post

2 REPLIES 2
hogi
Level XIII

Re: Use Xpath to delete outlier box from the window

Instead of

nw << XPath( "//Outlinebox[@helpKey = 'Summary Stats']" ) << delete;

please try

(nw << XPath( "//OutlineBox[text() = 'Summary Stats']" )) << delete;

- the brackets guarantee that the delete message is sent to the Outline Box.

- use OutlineBox instead of Outlinebox (one of the few cases where Jmp is case sensitive)

- text() = ... searches for the correct title


But perhaps

(nw << XPath( "//ScrollBox" )) << delete;

is what you want :)

Jackie_
Level VII

Re: Use Xpath to delete outlier box from the window

Thanks Hogi !

Recommended Articles