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- Replacing missing data by regressed values

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Jul 8, 2016 7:39 AM
(425 views)

Hi

I have a time series for which the variable has missing values. I would like to replace the missing values by a linear model derived from the closest available values in time.

What would be the best way?

And if the script could do that to all the columns of my table (except the time), that would be even better

Thanks

Example

What I have

t | Output |
---|---|

0 | 10 |

1 | . |

2 | . |

4 | 30 |

10 | . |

20 | 10 |

What I want:

t | Output |
---|---|

0 | 10 |

1 | 15 |

2 | 20 |

4 | 30 |

10 | 22.5 |

20 | 10 |

5 REPLIES

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Jul 8, 2016 9:08 AM
(299 views)

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Jul 10, 2016 2:31 PM
(299 views)

Thanks Ron but I don’t see anything in this that does interpolation?

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Jul 10, 2016 5:16 PM
(299 views)

here is a script that will do the task

**Names Default To Here( 1 );**

**dt = Current Data Table();**

**For( rows = 1, rows <= N Rows( dt ), rows++,**

** If( Rows == 1, counter = 0 );**

** If( Is Missing( dt:output[rows] ) == 1,**

** counter = counter + 1,**

** If( counter > 0,**

** incr = (dt:output[Rows] - dt:output[Rows - counter - 1]) / (counter + 1);**

** For( i = Rows - counter, i <= Rows - 1, i++,**

** dt:output = dt:output[i - 1] + incr**

** );**

** counter = 0;**

** )**

** );**

**);**

Jim

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Jul 10, 2016 5:47 PM
(299 views)

I had a similar problem some years ago and wrote a script to do imputation by "local regression".

Here's an updated version:

dt = Current Data Table**()**;

n = N Rows**(**dt**)**;

x = Column**(****1****)**;// Column("t")

For**(**i = **2**, i <= N Col**(**dt**)**, i++,

y = Column**(**i**)**;

For Each Row**(**

If**(****1** < Row**()** < n & Is Missing**(**y**[])**,

// find previous non-missing row

Eval**(**Eval Expr**(**r1 = Max**(**dt << **get rows where****(**!Is Missing**(**y**[])** & Row**()** < Expr**(**Row**())))))**;

// find next non-missing row

Eval**(**Eval Expr**(**r2 = Min**(**dt << **get rows where****(**!Is Missing**(**y**[])** & Row**()** > Expr**(**Row**())))))**;

y**[]** = y**[**r1**]** + **(**y**[**r2**]** - y**[**r1**])** / **(**x**[**r2**]** - x**[**r1**])** * **(**x**[]** - x**[**r1**])**;

**)**

**)**

**)**;

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Jul 11, 2016 1:28 AM
(299 views)