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- Replacing missing data by regressed values

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Jul 8, 2016 7:39 AM
(1547 views)

Hi

I have a time series for which the variable has missing values. I would like to replace the missing values by a linear model derived from the closest available values in time.

What would be the best way?

And if the script could do that to all the columns of my table (except the time), that would be even better

Thanks

Example

What I have

t | Output |
---|---|

0 | 10 |

1 | . |

2 | . |

4 | 30 |

10 | . |

20 | 10 |

What I want:

t | Output |
---|---|

0 | 10 |

1 | 15 |

2 | 20 |

4 | 30 |

10 | 22.5 |

20 | 10 |

5 REPLIES

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Jul 8, 2016 9:08 AM
(1421 views)

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Jul 10, 2016 2:31 PM
(1421 views)

Thanks Ron but I don’t see anything in this that does interpolation?

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Jul 10, 2016 5:16 PM
(1421 views)

here is a script that will do the task

**Names Default To Here( 1 );**

**dt = Current Data Table();**

**For( rows = 1, rows <= N Rows( dt ), rows++,**

** If( Rows == 1, counter = 0 );**

** If( Is Missing( dt:output[rows] ) == 1,**

** counter = counter + 1,**

** If( counter > 0,**

** incr = (dt:output[Rows] - dt:output[Rows - counter - 1]) / (counter + 1);**

** For( i = Rows - counter, i <= Rows - 1, i++,**

** dt:output = dt:output[i - 1] + incr**

** );**

** counter = 0;**

** )**

** );**

**);**

Jim

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Jul 10, 2016 5:47 PM
(1421 views)

I had a similar problem some years ago and wrote a script to do imputation by "local regression".

Here's an updated version:

dt = Current Data Table**()**;

n = N Rows**(**dt**)**;

x = Column**(****1****)**;// Column("t")

For**(**i = **2**, i <= N Col**(**dt**)**, i++,

y = Column**(**i**)**;

For Each Row**(**

If**(****1** < Row**()** < n & Is Missing**(**y**[])**,

// find previous non-missing row

Eval**(**Eval Expr**(**r1 = Max**(**dt << **get rows where****(**!Is Missing**(**y**[])** & Row**()** < Expr**(**Row**())))))**;

// find next non-missing row

Eval**(**Eval Expr**(**r2 = Min**(**dt << **get rows where****(**!Is Missing**(**y**[])** & Row**()** > Expr**(**Row**())))))**;

y**[]** = y**[**r1**]** + **(**y**[**r2**]** - y**[**r1**])** / **(**x**[**r2**]** - x**[**r1**])** * **(**x**[]** - x**[**r1**])**;

**)**

**)**

**)**;

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Jul 11, 2016 1:28 AM
(1421 views)

Spot on MS,

Cheers!