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Level II

## Peak of a probability distribution

Hi

I have a dataset which fits best to the Johnson Su distribution and I was wondering if there is a way to estimate the value of the peak of this distribution. It has just one peak, which is pretty different from the median or the mean. Calling this "mode" might be the best possible solution here but how do I estimate this point?

14 REPLIES 14
Level II

## Re: Peak of a probability distribution

Can the profile option be extended for data distribution that is grouped? For N groups, need to get the mode corresponding to distribution of each of the items in the group. Or should I subset by group everytime and then use the profiler option. I used the col groupby and then fitted but looks like it is giving a single value for entire dataset and not for each group member.

Staff

## Re: Peak of a probability distribution

Mark's way is really the best way to get the peak value, but for a quick way to get an estimated value you can fit the curve then use the JMP Crosshairs tool found in the Tools menu or on your menu bar.  Click the tool then put the crosshairs symbol on the spot you feel best represents the peak and a value will pop up.  If you are using JMP 13 you will get a magnifier with the Crosshair tool that will help you get close.

HTH

Staff

## Re: Peak of a probability distribution

Mark's method is neat. Here's an alternative that uses the function directly:

``````NamesDefaultToHere(1);
ClearLog();

// Make some representative data
dt = NewTable("Johnson Su", NewColumn("Data", Numeric, Continuous, Formula(Random Johnson Su( 5, 2, 1, 1 ))));

// Fit the data
dist = dt << Distribution(Continuous Distribution( Column( :Data ), Fit Distribution( Johnson Su ) ));
// Get the fitted parameters
params = Report(dist)[NumberColBox(3)] << get;
gamma = params[1];	// Shape
delta = params[2];	// Shape
theta = params[3];	// Location
sigma = params[4];	// Scale

// http://www.mathwave.com/articles/johnson_su_distribution.html
//			f(x) = delta/(lambda * Sqrt(2*pi()) * Sqrt(z^2 + 1)) * exp( -1/2*(gamma + delta * ln(z + Sqrt(z^2+1)))^2 );
// 		where:
//			z = (x - eta)/lambda;
//		and:
//			delta > 0 lambda > 0
jsu = Expr(delta/(lambda * Sqrt(2*pi()) * Sqrt(z^2 + 1)) * exp( -1/2*(gamma + delta * ln(z + Sqrt(z^2+1)))^2 ) );
SubstituteInto(jsu, Expr(z), Expr((x - eta)/lambda));
// Use the fitted parameter values
// Note the change in parameter names! 'lambda' -> 'sigma' and 'eta' -> 'theta'
SubstituteInto(jsu,
Expr(gamma), Eval(gamma),
Expr(delta), Eval(delta),
Expr(eta), Eval(theta),
Expr(lambda), Eval(sigma)
);
// Get upper and lower bounds for the optimisation (either side of the (assumed) single peak)
vals = Column(dt, "Data") << getValues;
low = Quantile(0.25, vals);
high = Quantile(0.75, vals);
// Do the maximization
Maximize(jsu, {x(low, high)}, << Tolerance(10^-10), << showDetails(true));
Print(x);
``````

('By eye' it seems to work, but no testing of course).

Staff

## Re: Peak of a probability distribution

One of the things that I love about JMP is that it often gives you many ways to solve a problem.  All of the previous suggestions for finding the mode of the fitted Johnson SU density for the data are great, but here is one more option that uses the Profiler.

Once you have used Distribution to fit the Johnson Su distribution to your data, you can choose Save Density Formula from the Fitted Johnson Su menu.  This saves the Johnson Su Density formula to a column in your data table.

Next you can open the Profiler by choosing Graph>>Profiler.  Cast your density formula as the Y, Prediction Formula and click OK.  Next turn on the Desirability Functions from Prediction Profiler menu.  After that you choose Maximize Desirability from the Prediction Profiler menu.  This will find the mode (maximum) of your Johnson Su density for this data.

Staff

## Re: Peak of a probability distribution

Laura's method is neater! And far less error prone. It's always best to let JMP do the work for you if you can figure out a way.