I think you might have to do this with a graphic script. Below is very quick and hacky solution, it can give an idea what you could possibly do
Names Default To Here(1);
dt = New Table("Untitled",
Add Rows(5),
Compress File When Saved(1),
New Column("SN", Numeric, "Continuous", Format("Best", 12), Set Values([1, 1, 1, 2, 2])),
New Column("X(cm)", Numeric, "Continuous", Set Values([2.2999999999999998, 2.7000000000000002, 1.5, 5.4000000000000004, 3.1000000000000001])),
New Column("Y(cm)", Numeric, "Continuous", Set Values([1.1499999999999999, 0.44, 2.6000000000000001, 1.8999999999999999, 4.0999999999999996])),
New Column("Diameter(cm)",
Numeric,
"Continuous",
Set Values([0.040000000000000001, 0.12, 0.34999999999999998, 0.17000000000000001, 0.58999999999999997])
)
);
gb = dt << Graph Builder(
Size(518, 454),
Show Control Panel(0),
Lock Scales(1),
Variables(X(:"X(cm)"n), Y(:"Y(cm)"n), Size(:"Diameter(cm)"n)),
Elements(Points(X, Y, Legend(5))),
Local Data Filter(Add Filter(columns(:SN), Modeling Type(:SN, Nominal)))
);
frame = Report(gb)[FrameBox(1)];
Eval(EvalExpr(
frame << Add Graphics Script(
cur_gb = Expr(Report(gb));
fb = cur_gb[FrameBox(1)];
ms = fb << Find Seg(Marker Seg(1));
xs = ms << Get X Values;
ys = ms << Get Y Values;
For(i = 1, i <= N Items(xs), i++,
dt = cur_gb << Get Data Table;
m_rows = dt << Get Rows Where(:"X(cm)"n == xs[i] & :"Y(cm)"n);
diam = dt[m_rows, "Diameter(cm)"][1];
Circle({xs[i], ys[i]}, diam/2);
);
);
));
Also read how Circle's radius behaves https://www.jmp.com/support/help/en/18.0/#page/jmp/graphics-functions.shtml?os=win&source=applicatio...
-Jarmo