Turn on suggestions

Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.

Showing results for

- JMP User Community
- :
- Discussions
- :
- Discussions
- :
- JSL Programming Challenge: Convert from string of Ys and Ns to matrix of 1s and ...

Topic Options

- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

May 17, 2018 12:57 PM
(1587 views)

Hi JSL programmers,

I had a little problem as part of a larger application and thought I'd share it with you, and see if there's a way to do it better/slicker.

Basically I have a vector of 1s and 0s (i.e. [1, 1, 0, 0, 1]) that I need to convert to a string of Ys and Ns (i.e. "YYNNY"). Then I need to do the reverse, that is convert a string of Ys and Ns back to a vector of 1s and 0s.

Here are my quick and dirty functions - let's see if you can come up with something beyond my feeble brainpower!

```
// Convert a vector of 1s and 0s to a string with no separators
matrix_10_to_yn = function({matrix_10}, {default local},
yn_txt = "";
if (nrows(matrix_10) > 0,
// Strip out square brackets and commas
yn_txt = substitute(char(matrix_10), "[", "", "]", "", ", ", "");
// Now convert 1s to Y and 0s to N
yn_txt = substitute(yn_txt, "1", "Y", "0", "N");
);
yn_txt;
);
// Convert a YN string with no separators to a vector of 1s and 0s
yn_to_matrix_10 = function({yn_txt}, {default local},
n = length(yn_txt);
matrix_10 = j(n, 1, 0);
for (i = 1, i <= n, i++,
if (substr(yn_txt, i, 1) == "Y",
matrix_10[i] = 1;
);
);
matrix_10;
);
```

// Test thing out
a = yn_to_matrix_10("YYYNNNN"); show(a);
b = matrix_10_to_yn(a); show(b);
c = yn_to_matrix_10(""); show(c);
d = matrix_10_to_yn(c); show(d);

5 ACCEPTED SOLUTIONS

Accepted Solutions

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Whatever works, works! Here is one alternative.

```
exmat = J(25,1, RandomInteger(0,1));
exlst = Insert({}, {"Y", "N"}[2-exmat]);
convert_yn = Function({usr}, {rslt, ynList ={"Y","N"} },
if(IsMatrix(usr),
rslt = insert({},ynList[2-usr])
, //else
rslt = J(nitems(usr),1, 1);
rslt[loc(usr,"N")]=0
); //end if
rslt
); //end Function
show(exmat, convert_yn(exmat), exlst, convert_yn(exlst));
```

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Another!!

```
Names Default to here(1);
yto1 = function({str},
{DEFAULT LOCAL},
list = words(str, "");
design(list, {"Y"});
);
oneToY = function({mat},
list = substitute(as list(mat), 1, "Y", 0, "N");
Concat items(list, "");
);
str = "YYYNNNNYYNY";
nums = yto1(str);
show(nums);
str2 = oneToY(nums);
show(str2, str2==str);
```

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

May 18, 2018 4:13 AM
(2302 views)
| Posted in reply to message from vince_faller 05/17/2018 07:54 PM

This won't extend to three values or missing/error values without some extra effort. It converts string--blob--matrix and does the Y and N detection using the number of the ASCII character in the matrix. The BlobToMatrix and MatrixToBlob functions are told to use 1-byte little-endian integers. The endianness is not critical for 1-byte numbers, big works just as well. It does depend on the characters having one byte representations.

```
source = "YYNNYQ";
// if you are uncomfortable with hard coded constants...
Yvalue = Blob To Matrix( Char To Blob( "Y" ), "int", 1, "little" )[1]; // 89
Nvalue = Blob To Matrix( Char To Blob( "N" ), "int", 1, "little" )[1]; // 78
// forward
numbers = Blob To Matrix( Char To Blob( source ), "int", 1, "little" ) == Yvalue;
// reverse
string = Blob To Char( Matrix To Blob( Nvalue + numbers * (Yvalue - Nvalue), "int", 1, "little" ) );
// display
Show( source, numbers, string );
```

source = "YYNNYQ";

numbers = [1, 1, 0, 0, 1, 0];

string = "YYNNYN";

Craige

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

you can do the string to matrix conversion in a single line using Char to Blob and Blob to Matrix. My contribution:

```
names default to here(1);
a=[1,0, 1, 1, 1, 0, 0, 1, 0, 1];
b="YNYYYNNYNY";
f_YNString_to_IndicatorVector=Function({s},
blob to matrix(char to blob(d),"int", 1, "little", 1)==89;
);
f_IndicatorVector_to_YNString=Function({v},{vv},
vv=As List(v);
vv[loc(v)]="Y";
vv[loc(!v)]="N";
concat items(vv,"");
);
show(a);
show(b);
Show(f_YNString_to_IndicatorVector(b));
Show(f_IndicatorVector_to_YNString(a));
Show(f_IndicatorVector_to_YNString(f_YNString_to_IndicatorVector(b)));
```

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

These are all very cool solutions. PMROZ pointed out that I misread that the secanrio is to start with a list. He asked for my revised solution. Below converts a list or a string of YN's to a vector of 10's and a vector of 10's to a string of YN's.

To be consistent with my previous post, I just converted the string to a list with the words() function using an empty string delimiter.

```
exmat = J(25,1, RandomInteger(0,1));
exlst = Insert({}, {"Y", "N"}[2-exmat]);
exstr = ConcatItems(Insert({}, {"Y", "N"}[2-exmat]), "");
convert_yn = Function({usr}, {rslt=empty(), ynList ={"Y","N"} },
if(IsMatrix(usr),
rslt = ConcatItems(insert({},ynList[2-usr]),"")
, //else
IsList(usr),
rslt = J(nitems(usr),1, 1);
rslt[loc(usr,"N")]=0
, //else
IsString(usr),
rslt = J(length(Trim(usr)),1,1);
rslt[loc(words(usr,""),"N")]=0
); //end if
rslt
); //end Function
show(exmat, convert_yn(exmat), exlst, convert_yn(exlst), exstr, convert_yn(exstr) );
```

11 REPLIES 11

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Whatever works, works! Here is one alternative.

```
exmat = J(25,1, RandomInteger(0,1));
exlst = Insert({}, {"Y", "N"}[2-exmat]);
convert_yn = Function({usr}, {rslt, ynList ={"Y","N"} },
if(IsMatrix(usr),
rslt = insert({},ynList[2-usr])
, //else
rslt = J(nitems(usr),1, 1);
rslt[loc(usr,"N")]=0
); //end if
rslt
); //end Function
show(exmat, convert_yn(exmat), exlst, convert_yn(exlst));
```

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Another!!

```
Names Default to here(1);
yto1 = function({str},
{DEFAULT LOCAL},
list = words(str, "");
design(list, {"Y"});
);
oneToY = function({mat},
list = substitute(as list(mat), 1, "Y", 0, "N");
Concat items(list, "");
);
str = "YYYNNNNYYNY";
nums = yto1(str);
show(nums);
str2 = oneToY(nums);
show(str2, str2==str);
```

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

May 18, 2018 4:13 AM
(2303 views)
| Posted in reply to message from vince_faller 05/17/2018 07:54 PM

This won't extend to three values or missing/error values without some extra effort. It converts string--blob--matrix and does the Y and N detection using the number of the ASCII character in the matrix. The BlobToMatrix and MatrixToBlob functions are told to use 1-byte little-endian integers. The endianness is not critical for 1-byte numbers, big works just as well. It does depend on the characters having one byte representations.

```
source = "YYNNYQ";
// if you are uncomfortable with hard coded constants...
Yvalue = Blob To Matrix( Char To Blob( "Y" ), "int", 1, "little" )[1]; // 89
Nvalue = Blob To Matrix( Char To Blob( "N" ), "int", 1, "little" )[1]; // 78
// forward
numbers = Blob To Matrix( Char To Blob( source ), "int", 1, "little" ) == Yvalue;
// reverse
string = Blob To Char( Matrix To Blob( Nvalue + numbers * (Yvalue - Nvalue), "int", 1, "little" ) );
// display
Show( source, numbers, string );
```

source = "YYNNYQ";

numbers = [1, 1, 0, 0, 1, 0];

string = "YYNNYN";

Craige

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

you can do the string to matrix conversion in a single line using Char to Blob and Blob to Matrix. My contribution:

```
names default to here(1);
a=[1,0, 1, 1, 1, 0, 0, 1, 0, 1];
b="YNYYYNNYNY";
f_YNString_to_IndicatorVector=Function({s},
blob to matrix(char to blob(d),"int", 1, "little", 1)==89;
);
f_IndicatorVector_to_YNString=Function({v},{vv},
vv=As List(v);
vv[loc(v)]="Y";
vv[loc(!v)]="N";
concat items(vv,"");
);
show(a);
show(b);
Show(f_YNString_to_IndicatorVector(b));
Show(f_IndicatorVector_to_YNString(a));
Show(f_IndicatorVector_to_YNString(f_YNString_to_IndicatorVector(b)));
```

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Re: JSL Programming Challenge: Convert from string of Ys and Ns to matrix of 1s and 0s, and back aga

May 18, 2018 5:00 AM
(1538 views)
| Posted in reply to message from MathStatChem 05/18/2018 07:59 AM

Oops, I didn't see Craig's reply...his version is better, I think.

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Re: JSL Programming Challenge: Convert from string of Ys and Ns to matrix of 1s and 0s, and back aga

May 18, 2018 5:14 AM
(1535 views)
| Posted in reply to message from MathStatChem 05/18/2018 08:00 AM

Wow these are amazing. Thanks all!

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Re: JSL Programming Challenge: Convert from string of Ys and Ns to matrix of 1s and 0s, and back aga

and now I need to study the design() function!

Craige

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Re: JSL Programming Challenge: Convert from string of Ys and Ns to matrix of 1s and 0s, and back aga

@pmroz,

Here is my take/attempt at this. Thanks for offering this interesting challenge. I know I am using a loop which I don't know if it will scale well over large matrices, but I thought, some others in the community can come up with a faster way.

```
Clear Log(); Clear Globals();
ex = Associative Array({1,0} ,{"Y", "N"});
Test = [1,0, 1, 1, 1, 0, 0, 1, 0, 1];
Res = {};
for(i = 1, i <= N Rows(Test), i++,
Insert Into(Res, ex << Get Value(Test[i]));
);
Show(Res);
```

Best

Uday

Uday

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Get Direct Link
- Email to a Friend
- Report Inappropriate Content

Re: JSL Programming Challenge: Convert from string of Ys and Ns to matrix of 1s and 0s, and back aga

I use a generic 'mapply' function in most projects, so normally I would only need the last two lines:

```
Names Default to here(1);
// Utility function to make for loops, combo 'map' and 'apply'
// this is a 'fake' map/apply function because it allows side
// effects (like apply) and it also returns a value (like map)
mapply = function( {x, foo, arg1 = "__missing", arg2 = "__missing"}, { i, r = {}, x, foo, arg1, arg2, arg1missing, arg2missing },
if( N Items( x ) < 1,
return({}), //empty list supplied, return an empty list
for( i = 1, i <= N Items(x), i++,
arg1missing = 0; arg2missing = 0;
If( type(arg1) == "String", If( arg1 == "__missing", arg1missing = 1 ) );
If( type(arg2) == "String", If( arg2 == "__missing", arg2missing = 1 ) );
if(
arg1missing == 1,
r = Insert( r, foo( x[i] ) ),
arg2missing == 1,
r = Insert( r, foo( x[i], arg1 ) ),
r = Insert( r, foo( x[i], arg1, arg2 ) )
)
)
);
return(r);
);
// Solution:
str = "YYYNNNNYYNY";
(numbers = mapply( words(str,""), function( {x}, if( x=="Y", 1, 0) ) ) )
mapply( as list(numbers), function( {x}, if( x==1,"Y", "N") ) )
```