- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Get Direct Link
- Report Inappropriate Content
Intercept of a parabola
Hi,
While using JMP's "Fit Y by X" platform to fit data with a quadratic model, I observed that the intercept obtained using JMP’s centered polynomial notation for a parabola differs from the intercept obtained using the standard (uncentered) ( y = ax^2 + bx + c ) format. Based on my understanding, the intercept represents the value of ( Y ) when ( x = 0 ), and I don't see why these values should differ according to the notation used.
I have attached an example using the equation ( y = 203x^2 - 3x + 1000 ). The uncentered model correctly indicates that the intercept is 1000, whereas the centered notation shows the value -125875, a significantly different result.
I have tried to find an explanation for this discrepancy in JMP's help documentation and within the community forums, but I have been unsuccessful so far. Therefore, I would appreciate it if someone could clarify what I might be missing here.
Many thanks,
Paulo
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Get Direct Link
- Report Inappropriate Content
Re: Intercept of a parabola
The Fit Y by X default option is a centered polynomial fit centered around the mean (xavg) of the X factor.
Uncentered polynomial (what you are looking for): y = ax^2 + bx + c
Centered polynomial: y = A(x-xavg)^2 + Bx + C = Ax^2 - 2A*xavg*x + Bx + A*xavg^2 + C
So comparing term for term:
a = A
b = -2A*xavg + B
c = A*xavg^2 + C
So you can use these formulas to calculate the uncentered fit coefficients, or fit an uncentered polynomial from Fit Special.
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Get Direct Link
- Report Inappropriate Content
Re: Intercept of a parabola
Thanks, @mzwald.
- « Previous
-
- 1
- 2
- Next »