This website uses Cookies. Click Accept to agree to our website's cookie use as described in our Privacy Policy. Click Preferences to customize your cookie settings.
Accept
Reject
Preferences
cancel
Turn on suggestions
Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.
Showing results for 
Show  only  | Search instead for 
Did you mean: 
Choose Language Hide Translation Bar
Hester
Hester
Level I

If a column contains "%"--> how can I use this type for a formula? i.e. if states "%" do formula, otherwise use a number from another column?

Created: Aug 16, 2021 05:55 AM  |  Last Modified: Jun 9, 2023 03:54 PM (199 views)

I'm struggling. I have a column which contains either %, /nl or 10^9 as a outcome. the linked numbers in another column have to be converted depending on these expressions. How should I use the column properties and which comparison or expression in the formula should I use? Most use a numerical part for this, but I need now the characters.

 

if --> % than calculate number *100, if not do xxx

0 Kudos
1 REPLY 1
Craige_Hales
Super User Craige_Hales
Super User

Re: If a column contains "%"--> how can I use this type for a formula? i.e. if states "%" do formula, otherwise use a number from another column?

Aug 16, 2021 06:32 AM (194 views)  |  Posted in reply to message from Hester 08-16-2021

A picture would help. Is the column a character column, showing the % or / or ^ ? Or is it a numeric column with just a number?

If it is a character column, the contains() function might do what you need.

 

contains("37%", "%")
3 // position of the %

contains("37%", "/")
0 // / not found (position 0 not a valid position)
Craige
0 Kudos