How to make control/trend charts with multiple x axis variables?

[#1]

Hi all,

I want to create a "control chart-like" graph. Essentially, it is like a control chart, but the x variables can be as many as I like. It is like the graph I attached, but with a line passing through all the points.

Here are some solutions I tried but failed:

• Variability Chart ==> I can't draw the connecting line across the points.
• Line Chart ==> The x variable number is limited to two.
• Graph builder ==> Too tedious with its unpredictable drag and drop mechanism. Also, my third variable is a date (numeric type) which is not added, no matter how hard I try to drag it at x-axis.

Any suggestions?

Thank you,

Shaira

[#2 · Accepted solution]

GraphBuilder is predictable once you get used to how the drop zones work. Take a look here. Running the script below shows the result in a simple case.

NamesDefaultToHere(1);
dt = Open("$SAMPLE_DATA/Big Class.jmp");
dt << Graph Builder(
			Size( 894, 595 ),
			Show Control Panel( 0 ),
			Variables(
				X( :age ),
				X( :sex, Position( 1 ) ),
				X( Transform Column( "Row", Ordinal, Formula( Row() ) ), Position( 1 ) ),
				Y( :height )
			),
			Elements(
				Line( X( 1 ), X( 2 ), X( 3 ), Y, Legend( 6 ) ),
				Points( X( 1 ), X( 2 ), X( 3 ), Y, Legend( 7 ) )
			)
		);

[#3]

Thank you Ian! This is exactly what I need. Let me try this with my own data.

Best Regards,

Shaira

[#4]

Hi @ian_jmp and others

I am trying to modify the script you sent, hence may I ask the ff questions?

1. Regarding these lines

Elements(
				Line( X( 1 ), X( 2 ), X( 3 ), Y, Legend( 6 ) ),
				Points( X( 1 ), X( 2 ), X( 3 ), Y, Legend( 7 ) )

What does the number arguments mean? I.e. What do the numbers 1, 2, 3, 6, 7 mean?

2. I wanted to color the points by a grouping column but maintain a single color for the connecting line, I tried doing it manually first. I ended up coloring both the points and line. I manually edited it and saved the script. The saved script looks ugly (see below). Do you know an alternative way of doing it by jsl? I am thinking of combining for loop and eval(parse(string) expressions as a backup solution.

			{Legend Model(
				6,
				Properties( 0, {Line Color( 19 )} ),
				Properties( 1, {Line Color( 19 )} ),
				Properties( 2, {Line Color( 19 )} ),
				Properties( 3, {Line Color( 19 )} ),
				Properties( 4, {Line Color( 19 )} ),
				Properties( 5, {Line Color( 19 )} ),
				Properties( 6, {Line Color( 19 )} ),
				Properties( 7, {Line Color( 19 )} ),
				Properties( 8, {Line Color( 19 )} ),
				Properties( 9, {Line Color( 19 )} ),
				Properties( 10, {Line Color( 19 )} ),
				Properties( 11, {Line Color( 19 )} ),
				Properties( 12, {Line Color( 19 )} ),
				Properties( 13, {Line Color( 19 )} ),
				Properties( 14, {Line Color( 19 )} ),
				Properties( 15, {Line Color( 19 )} ),
				Properties( 28, {Line Color( 19 )} ),
				Properties( 29, {Line Color( 19 )} ),
				Properties( 30, {Line Color( 19 )} ),
				Properties( 31, {Line Color( 19 )} ),
				Properties( 32, {Line Color( 19 )} )
			), Legend Model(
				7,
				Base( 0, 0, 0 ),
				Base( 1, 0, 0 ),
				Base( 2, 0, 0 ),
				Base( 3, 0, 0 ),
				Base( 4, 0, 0 ),
				Base( 5, 0, 0 ),
				Base( 6, 0, 0 ),
				Base( 7, 0, 0 ),
				Base( 8, 0, 0 ),
				Base( 9, 0, 0 ),
				Base( 10, 0, 0 ),
				Base( 11, 0, 0 ),
				Base( 12, 0, 0 ),
				Base( 13, 0, 0 ),
				Base( 14, 0, 0 ),
				Base( 15, 0, 0 ),
				Base( 16, 0, 0 ),
				Base( 17, 0, 0 ),
				Base( 18, 0, 0 ),
				Base( 19, 0, 0 ),
				Base( 20, 0, 0 ),
				Base( 21, 0, 0 ),
				Base( 22, 0, 0 ),
				Base( 23, 0, 0 ),
				Base( 24, 0, 0 ),
				Base( 25, 0, 0 ),
				Base( 26, 0, 0 ),
				Base( 27, 0, 0 ),
				Base( 28, 0, 0 ),
				Base( 29, 0, 0 ),
				Base( 30, 0, 0 ),
				Base( 31, 0, 0 ),
				Base( 32, 0, 0 ),
				Properties( 0, {Line Color( 0 )} )
			)}

3. The legend in graph builder is static (i.e. if I click a certain group, it does not highlight the points corresponding to it). This is a really nice feature in Bivariate and Variability graphs. Is there a workaround for this? This is just minor, I can use the JMP filter to accomplish this if there is no workaround.

Thank you very much,

Shaira

[#5]

Hi @ian_jmp and others,

I am trying to edit the script above. Hence, the ff questions.

1. What does the number inputs (1, 2, 3, 6, and 7) mean?

Elements(
				Line( X( 1 ), X( 2 ), X( 3 ), Y, Legend( 6 ) ),
				Points( X( 1 ), X( 2 ), X( 3 ), Y, Legend( 7 ) )

2. How do I add legend box in graph builder where the colors are determined by grouping column, but the connector line is a single color?

Solutions I tried:

a. Manually doing it and saving the JSL script. I ended up with an ugly script below.

b. Not yet tried. Simplify the ugly script in (a) using for loops and Eval(parse()) functions.

	SendToReport(
		Dispatch(
			{},
			"X Variable Name",
			ScaleBox,
			{Show Major Grid( 1 ), Show Minor Grid( 1 ),
			Rotated Labels( "Perpendicular" )}
		),
		Dispatch(
			{},
			"400",
			ScaleBox,
			{Legend Model(
				6,
				Properties( 0, {Line Color( 19 )} ),
				Properties( 1, {Line Color( 19 )} ),
				Properties( 2, {Line Color( 19 )} ),
				Properties( 3, {Line Color( 19 )} ),
				Properties( 4, {Line Color( 19 )} ),
				Properties( 5, {Line Color( 19 )} ),
				Properties( 6, {Line Color( 19 )} ),
				Properties( 7, {Line Color( 19 )} ),
				Properties( 8, {Line Color( 19 )} ),
				Properties( 9, {Line Color( 19 )} ),
				Properties( 10, {Line Color( 19 )} ),
				Properties( 11, {Line Color( 19 )} ),
				Properties( 12, {Line Color( 19 )} ),
				Properties( 13, {Line Color( 19 )} ),
				Properties( 14, {Line Color( 19 )} ),
				Properties( 15, {Line Color( 19 )} ),
				Properties( 28, {Line Color( 19 )} ),
				Properties( 29, {Line Color( 19 )} ),
				Properties( 30, {Line Color( 19 )} ),
				Properties( 31, {Line Color( 19 )} ),
				Properties( 32, {Line Color( 19 )} )
			), Legend Model(
				7,
				Base( 0, 0, 0 ),
				Base( 1, 0, 0 ),
				Base( 2, 0, 0 ),
				Base( 3, 0, 0 ),
				Base( 4, 0, 0 ),
				Base( 5, 0, 0 ),
				Base( 6, 0, 0 ),
				Base( 7, 0, 0 ),
				Base( 8, 0, 0 ),
				Base( 9, 0, 0 ),
				Base( 10, 0, 0 ),
				Base( 11, 0, 0 ),
				Base( 12, 0, 0 ),
				Base( 13, 0, 0 ),
				Base( 14, 0, 0 ),
				Base( 15, 0, 0 ),
				Base( 16, 0, 0 ),
				Base( 17, 0, 0 ),
				Base( 18, 0, 0 ),
				Base( 19, 0, 0 ),
				Base( 20, 0, 0 ),
				Base( 21, 0, 0 ),
				Base( 22, 0, 0 ),
				Base( 23, 0, 0 ),
				Base( 24, 0, 0 ),
				Base( 25, 0, 0 ),
				Base( 26, 0, 0 ),
				Base( 27, 0, 0 ),
				Base( 28, 0, 0 ),
				Base( 29, 0, 0 ),
				Base( 30, 0, 0 ),
				Base( 31, 0, 0 ),
				Base( 32, 0, 0 ),
				Properties( 0, {Line Color( 0 )} )
			)}
		),
		Dispatch(
			{},
			"400",
			LegendBox,
			{Position(
				{-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
				-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 0, 1,
				2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
				21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32}
			)}
		)
	)

3. Is the legend box in graph builder really static? In Bivariate and Variability graphs, clicking the legend box highlights the points corresponding to clicked group. But, this is just minor concern. I can use the JMP filter as an alternative solution for this.

Thank you very much for the help,

Shaira

[#6]

Unless I really need to, I tend not to worry about interpreting the 'low level' code that JMP generates for me.

Using the example above, exposing the Control Panel and dragging 'age' to the 'Color' drop zone, I made:

The resulting legend is selctable.

Then, looking at the options on the left and deselecting one, I made:

which (I think) is what you want