Graph Builder- remove data series

[#1]

Hi again,

I have two sets of x and y data.  Using the graph builder, I drag X1 to group x on the bottom and Y1 on group y on the left.  Then I drag X2 to group x on the bottom, and Y2 to group y on the left.  I dragged the second sets of data to the middle of the group so that it is not a split plot.

Now I have four sets of data, and I only want two.  In the legend it says, Y1/X1, Y2/X1, Y1/X2 and Y2/X2.  Is it possible to remove two of those series so that I only have Y1/X1 and Y2/X2? 

[#2 · Accepted solution]

Right click on the legend entry that you don't want (Y1/X2) and select Transparency.  Set the transparency to 0.  Then do the same for Y2/X1.  Then double-click the legend and uncheck the entries for Y1/X2 and Y2/X1.

Try running this code:

dt = New Table( "X1 Y1 X2 Y2", Add Rows( 5 ),

      New Column( "x1", Numeric, Continuous, Format( "Best", 12 ),

            Set Values( [1, 2, 3, 4, 5] )

      ),

      New Column( "y1", Numeric, Continuous, Format( "Best", 12 ),

            Set Values( [1, 2, 3, 1, 2] )

      ),

      New Column( "x2", Numeric, Continuous, Format( "Best", 12 ),

            Set Values( [2, 3, 4, 5, 6] )

      ),

      New Column( "y2", Numeric, Continuous, Format( "Best", 12 ),

            Set Values( [4, 5, 6, 4, 5] )

      )

);

dt << Graph Builder(

      Show Control Panel( 0 ),

      Variables(

            X( :x1 ),

            X( :x2, Position( 1 ) ),

            Y( :y1 ),

            Y( :y2, Position( 1 ) )

      ),

      Elements( Points( X( 1 ), X( 2 ), Y( 1 ), Y( 2 ), Legend( 7 ), Jitter( 1 ) ) ),

      SendToReport( Dispatch( {}, "400", ScaleBox,

                  {Legend Model( 7,

                        Properties( 1, {Transparency( 0 )} ),

                        Properties( 2, {Transparency( 0 )} )

                  )}

            ),

            Dispatch( {}, "400", LegendBox, {Position( {0, -1, -1, 1} )} )

      )

);

[#3]

Thank you!  I thought I just needed to remove it from the legend to remove it from the plot.

I will definitely be using that piece of code, too.  Thanks again!