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DoE CCD
Hello,
I created a series of experiments using DoE (effect surface design). After conducting the experiments, I obtained a Pareto chart at a significance level of 0.02, in which a reference line (blue line) is drawn. I would like to know what value my reference line is? Can I have the value calculated?
Thank you very much
Greetings
This post originally written in German and has been translated for your convenience. When you reply, it will also be translated back to German.
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Re: DoE CCD
Hi @ZE : Welcome to the forum. It is the critical value from the t distribution. It depends on alpha (0.05 by default) and the error degrees of freedom (from the ANOVA table). In JMP they are calculated (+/-), respectively, as shown below (where df = Error DF from ANOVA table).
-t Quantile( 0.975, df ), t Quantile( 0.975, df )
This is explained in the Sorted Estimates help:
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Re: DoE CCD
Hi MRB3855
Thanks for the quick reply. I had 15 runs and set the alpha value to 0.02. Is there no way in the software to give me the value for the blue line (reference line)? I would like to create a diagram for my report and need the value for this line. In Minitab, I was given a value of 3.36 for the blue reference line.
Many thanks in advance.
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Re: DoE CCD
Hi @ZE Here ya go.
t Quantile( 0.01, 5 ) and t Quantile( 0.99, 5 )
In general, t Quantile (alpha/2, Error df) and t Quantile ( 1-alpha/2, Error df)
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Re: DoE CCD
Hi @MRB3855
I appreciate that. The main problem is that I don't get the same value as with Minitab (critical t-value = 3.36) and that makes me a bit unsure. I have 3 factors that have changed in three levels and occur 5 times each in the trials (15). So I have 14 DF and when I read the t-value at the 0.02 and 14 DF significance levels, I get 2.62.
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Re: DoE CCD
Hi @ZE : You have 15 total runs? If so, you have 9 terms (3 main effects, 3 quadratic effects, and 3 pairwise interactions) in your model and that leaves only 5 df for Error. So 3.36 is correct; you have 14 df Total, but it is the Error df that matters.
Or am I misunderstanding?
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Re: DoE CCD
Hi @MRB3855
no, you're right. i'm sorry, i made a small logical mistake and always calculated with the total degree of freedom.