can some one help me in using eval expr() function with column name;
is the above evel expr() refers to names column? if so please help me with the syntax..(for referring column names)
This will get you what you want. . .
var = parse(":"||temp);
However, a better general implementation that will work no matter how the column is named is to use:
var = Parse(":Name(\!"" || (col << Get Name()) || "\!")");
where col is a column reference (if you already have it). If you don't you can replace the middle part of the concatenation with column1 from above (or the string "names" itself).
If this question is not answered, I guess I do not understand the question. Here is another answer . . .
In this case, eval expr() is not working as I would expect. However, I almost never use eval expr() instead I would write
column1 = "names";
val = Eval(Expr(":" || column1));
If you run this, val = ":names"
Alternatively, you could simply write
val = Eval(":" || column1);
val = ":" || column1;
However, if you want to actually refer to the column whose name is "names" then you will have to parse val. . .
val2 = parse(val);
Now you can, for example, get the value in row one of this column by running val2.
If your question is not answered at this point, please restate your question.