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Dec 13, 2017 8:06 AM
(2182 views)

I have a large dataset with around 30 columns of time-dated financial entries. I want to know which column is the first with a nonzero (no columns have missing data, but I want to get the first column with a positive value entry) value. I've attached a small made-up example with four time columns and a fifth column showing what I'd like my formula to result in. If the zero values were missing, I could use the function for Number (number of nonmissing values) to get what I want, but when there is no missing data and zero values, I can't figure out how to automate identifying which column is the first that has a positive value. Any ideas will be appreciated.

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@dale_lehman,

Couple of thoughts and solutions here to your problem .

Approach 1 : Continue with JSL from previous solution and add it to table

```
dt = Current Data Table();
Mat = dt << Get As Matrix;
DesList = list();
for(i = 1 , i <= N Rows(Mat), i++,
Pos = Min(Loc(Mat[i,0]));
Insert Into(DesList,Pos);
);
dt << New Column("Test",Numeric,Continuous,<< Set Values(DesList));
// Please note that there will be "." missing value if none of your columns have a positive value
```

Approach 2 : Script the formula in JSL and apply it to the table - a little roundabout - but scaleable - an old but relevant example - will edit later in the day

```
for(i = 1, i <= N Items(InvColNames), i++,
If(i == 1,
Stmt = ":" || InvColNames[i] || " >= 1 &" || ":" || InvColNames[i] || " <= InvLimit" ;
,
Stmt = Stmt || " & " || ":" || InvColNames[i] || ">= 1 &" || ":" || InvColNames[i] || " <= InvLimit" ;
) ;
);
Eval( Parse( Eval Insert("\[ dt_Inp << New Column("Status_Inv",Numeric,Continuous,Formula(^Stmt^)); ]\" ) ) );
```

Approach 3 : Manually do something like this - not a fan of this, but can't seem to find an alternative by myself - maybe others will have better thoughts

```
If(
:Column 1 > 0, "Column 1",
:Column 2 > 0, "Column 2",
"No Positive"
)
```

Best

Uday

Uday

3 REPLIES 3

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Re: need help identifying first nonzero column

@dale_lehman,

Maybe try this ?

```
dt = Current Data Table();
Mat = dt << Get As Matrix;
DesList = list();
for(i = 1 , i <= N Rows(Mat), i++,
Pos = Min(Loc(Mat[i,0]));
Insert Into(DesList,Pos);
);
Show(DesList);
```

Best

Uday

Uday

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Re: need help identifying first nonzero column

- Mark as New
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@dale_lehman,

Couple of thoughts and solutions here to your problem .

Approach 1 : Continue with JSL from previous solution and add it to table

```
dt = Current Data Table();
Mat = dt << Get As Matrix;
DesList = list();
for(i = 1 , i <= N Rows(Mat), i++,
Pos = Min(Loc(Mat[i,0]));
Insert Into(DesList,Pos);
);
dt << New Column("Test",Numeric,Continuous,<< Set Values(DesList));
// Please note that there will be "." missing value if none of your columns have a positive value
```

Approach 2 : Script the formula in JSL and apply it to the table - a little roundabout - but scaleable - an old but relevant example - will edit later in the day

```
for(i = 1, i <= N Items(InvColNames), i++,
If(i == 1,
Stmt = ":" || InvColNames[i] || " >= 1 &" || ":" || InvColNames[i] || " <= InvLimit" ;
,
Stmt = Stmt || " & " || ":" || InvColNames[i] || ">= 1 &" || ":" || InvColNames[i] || " <= InvLimit" ;
) ;
);
Eval( Parse( Eval Insert("\[ dt_Inp << New Column("Status_Inv",Numeric,Continuous,Formula(^Stmt^)); ]\" ) ) );
```

Approach 3 : Manually do something like this - not a fan of this, but can't seem to find an alternative by myself - maybe others will have better thoughts

```
If(
:Column 1 > 0, "Column 1",
:Column 2 > 0, "Column 2",
"No Positive"
)
```

Best

Uday

Uday