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Created:
Jan 8, 2019 9:40 AM
| Last Modified: Jan 8, 2019 9:41 AM
(4886 views)

For example, I have a char column

Column 1

Cordinate1:N23; Cordinate2:S45

Cordinate1:S78; Cordinate2:N85

Cordinate1:N67; Cordinate2:N90

Cordinate1:S33; Cordinate2:S74

Now I am only interested in the infonation for Cordinate2 North, so I would like to create a new column by using some formula to extract the Cordinate2 N data. The results should look like this:

Column 1 Column2

Cordinate1:N23; Cordinate2:S45 Do not care

Cordinate1:S78; Cordinate2:N85 N85

Cordinate1:N67; Cordinate2:N90 N90

Cordinate1:S33; Cordinate2:S74 Do not care

Thanks a lot!

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Use this expression in a column formula:

`Regex( text, "Cordinate2:(N\d+)", "\1" );`

Learn it once, use it forever!

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Here's a column formula that will give you only North Coordinates. It makes a few assumptions like they'll always be in this format.

```
txt = Word( 2, Substitute( :Column 1, "Cordinate1", "", "Cordinate2", "" ), ":; " );
If( Left( txt, 1 ) == "N",
txt,
""
);
```

Vince Faller - Predictum

5 REPLIES 5

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Use this expression in a column formula:

`Regex( text, "Cordinate2:(N\d+)", "\1" );`

Learn it once, use it forever!

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Re: How to extract part of char string in a column by using formula

Created:
Jan 8, 2019 9:58 AM
| Last Modified: Jan 8, 2019 10:13 AM
(4879 views)
| Posted in reply to message from markbailey 01-08-2019

Thanks Mark. Could you please explain the formula a little bit? so I can adapt it to my real data table. For example, sometimes I need use Cordinate1 North as serach pattern and exact Cordinate 2 info, like the results below. How can I adapt the formula? Thank you!

Column 1 Column2

Cordinate1:N23; Cordinate2:S45 S45

Cordinate1:S78; Cordinate2:N85 Do not care

Cordinate1:N67; Cordinate2:N90 N90

Cordinate1:S33; Cordinate2:S74 Do not care

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Re: How to extract part of char string in a column by using formula

I will assume that you know nothing about *regular expressions*. The character function **Regex**( "text", "regular expression", "result format" ) matches patterns defined by the regular expression in the text and returns the result as defined by the format argument. You can refer to this topic in **Help** > **Books** > **Scripting Guide** for more details. An alternative approach could be built around JMP *patterns* and their related functions. The **Scripting Guide** also covers that topic.

How does the need for this adaptability arise? Does it depend in the data problem (i.e., a new problem and new data set) or does it have to handle more than one condition in the same result data column?

The regular expression are generally quite specific, so the adaptation would require specifying all of the conditions to be found.

Learn it once, use it forever!

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Here's a column formula that will give you only North Coordinates. It makes a few assumptions like they'll always be in this format.

```
txt = Word( 2, Substitute( :Column 1, "Cordinate1", "", "Cordinate2", "" ), ":; " );
If( Left( txt, 1 ) == "N",
txt,
""
);
```

Vince Faller - Predictum

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Re: How to extract part of char string in a column by using formula

Thanks!

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