cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 
  • Learn how to build custom Python data connectors and further customize JMP’s Data Connector Framework with the Python Data Connector Demo, available now in the JMP Marketplace!
  • See how to create experiments to support product design and ID useful product features. Register for June 12 webinar, 2pm US Eastern Time.

Discussions

Solve problems, and share tips and tricks with other JMP users.
Choose Language Hide Translation Bar
Thierry_S
Super User

How to convert string into dates. Example: 06-AUG-2018 --> Date

Hi JMP community,

 

I would like to know if there is a more efficient way to translate a date string in the format 06-AUG-2018 into a JMP date.

 

Here is what I have used in the past:

Local( {t1},
	t1 = Match( Word( 2, :Date of Collection, "-" ),
		"JAN", 1,
		"FEB", 2,
		"MAR", 3,
		"APR", 4,
		"MAY", 5,
		"JUN", 6,
		"JUL", 7,
		"AUG", 8,
		"SEP", 9,
		"OCT", 10,
		"NOV", 11,
		12
	);
	Date MDY(
		t1,
		Num( Word( 1, :Date of Collection, "-" ) ),
		Num( Word( 3, :Date of Collection, "-" ) )
	);
)

Where "Date of Collection" is the string date.

I also tried the "In Format" function but I could not figure out how to make JMP understand the abbreviated month (e.g. JAN, FEB...).

 

Thank you for your help.

 

Sincerely,

 

TS

Thierry R. Sornasse
1 ACCEPTED SOLUTION

Accepted Solutions
Jeff_Perkinson
Community Manager Community Manager

Re: How to convert string into dates. Example: 06-AUG-2018 --> Date

Informat will work for you. No need to specify an input format.

 

d="06-AUG-2018";

d1="02-JAN-2016";

d2="08-DEC-1998";


x=informat(d);

x1=informat(d1);

x2 = informat(d2);

show(x, x1, x2);

/*:

x = 06Aug2018;
x1 = 02Jan2016;
x2 = 08Dec1998;
-Jeff

View solution in original post

1 REPLY 1
Jeff_Perkinson
Community Manager Community Manager

Re: How to convert string into dates. Example: 06-AUG-2018 --> Date

Informat will work for you. No need to specify an input format.

 

d="06-AUG-2018";

d1="02-JAN-2016";

d2="08-DEC-1998";


x=informat(d);

x1=informat(d1);

x2 = informat(d2);

show(x, x1, x2);

/*:

x = 06Aug2018;
x1 = 02Jan2016;
x2 = 08Dec1998;
-Jeff

Recommended Articles