Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.

Showing results for

- JMP User Community
- :
- Discussions
- :
- Discussions
- :
- How to best fit data to a plane or line

- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Feb 26, 2015 8:06 AM
(3080 views)

Hello

I was wondering if there is a way in JMP that I could use to take raw data of multiple measurement points (each with an X, Y, Z component) and best fit this data to form a best fit plane. Basically my intent is to take raw metrology data off of OMMs/CMMs and fit them myself without the use of CMM/OMMs measurement software.

Thanks for your help!

Solved! Go to Solution.

1 ACCEPTED SOLUTION

Accepted Solutions

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Feb 26, 2015 10:04 AM
(4718 views)

Solution

I used **ax + by + cz = d** as a starting point to generate some slightly random data like this:

dt = New Table( "Untitled",

Add Rows( 20 ),

New Table Variable( "a", 5 ),

New Table Variable( "b", 7 ),

New Table Variable( "c", 11 ),

New Table Variable( "d", 13 ),

New Column( "x", Formula( Random Uniform() * 10 ) ),

New Column( "y", Formula( Random Uniform() * 10 ) ),

New Column( "z", Formula( Random Normal() / 2 + (:d - (:a * :x + :b * :y)) / :c ) )

);

which makes Z a function of X and Y, approximately on the plane defined by A, B, C, D.

Next, use Analyze->Fit Model and put in Z as the Y (response) and ADD X and Y to the model effects. Click Run. The parameter Estimates are what I think you are looking for. I get this, for my random numbers:

to convert these back to the A=5, B=7, C=11, D=13 form, rearrange the formula as

and see d/c is 13/11 is 1.1818 (close to 1.179) a/c is 5/11 is .4545 (close to .4555) and b/c is 7/11 is .6363 (close to .6355). Watch the signs. You can see the surface in the Fit Least Squares window; red triangle menu->Factor Profiling->Surface Profiler. Under Appearance turn on the Actual points.

In the platform you can rotate the surface to clearly see the points above and below the plane. Try clicking the points to select them. This picture doesn't do it justice...

Craige

4 REPLIES

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Feb 26, 2015 10:04 AM
(4719 views)

I used **ax + by + cz = d** as a starting point to generate some slightly random data like this:

dt = New Table( "Untitled",

Add Rows( 20 ),

New Table Variable( "a", 5 ),

New Table Variable( "b", 7 ),

New Table Variable( "c", 11 ),

New Table Variable( "d", 13 ),

New Column( "x", Formula( Random Uniform() * 10 ) ),

New Column( "y", Formula( Random Uniform() * 10 ) ),

New Column( "z", Formula( Random Normal() / 2 + (:d - (:a * :x + :b * :y)) / :c ) )

);

which makes Z a function of X and Y, approximately on the plane defined by A, B, C, D.

Next, use Analyze->Fit Model and put in Z as the Y (response) and ADD X and Y to the model effects. Click Run. The parameter Estimates are what I think you are looking for. I get this, for my random numbers:

to convert these back to the A=5, B=7, C=11, D=13 form, rearrange the formula as

and see d/c is 13/11 is 1.1818 (close to 1.179) a/c is 5/11 is .4545 (close to .4555) and b/c is 7/11 is .6363 (close to .6355). Watch the signs. You can see the surface in the Fit Least Squares window; red triangle menu->Factor Profiling->Surface Profiler. Under Appearance turn on the Actual points.

In the platform you can rotate the surface to clearly see the points above and below the plane. Try clicking the points to select them. This picture doesn't do it justice...

Craige

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Feb 26, 2015 2:27 PM
(2687 views)

Thanks for the response. I used the fit model platform as instructed and it worked perfectly.

Do you have any ideas on how to un-fit the data? Basically if I have X, Y and the equation for Z is there a way to determine what the original Z was?

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Feb 26, 2015 2:57 PM
(2687 views)

red triangle->SaveColumns->PredictionFormula will add a formula column to the table which shows the predicted value for an (X,Y). It will generally not be exactly the same as any of your original data points. Perhaps what you want to see is the differences between the original and predicted column...saveColumns->Residuals.

It sounds like you might want something else though. Can you explain what you are trying to do? A graph perhaps, similar to the surface plot? Or some sort of query system to retrieve the data?

Craige

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Feb 27, 2015 2:32 AM
(2687 views)