How can I create a mean line of multiple data sets?

[#1]

Hi,

I am plotting 23 different stress vs strain data sets (see photo below) and I would like to create the mean curve for the combined 23. Each data set has approximately 9000 data points, that is why this graph looks like curves-- but it is a scatter plot.

Any help is greatly appreciated!

Thanks,

Ilsa

[#2]

Create a new column and call it "Mean" and give it the formula of

Mean(:iL, :2L, :3L, 4L, 5L ………...25L)

Then include it in your graph

[#3]

Did you mean:

Mean(:1L, :2L, :3L, :4L, :5L, :6L, :7L, :8L, :9L, :10L, :11L, :12L, :13L, :14L, :15L, :16L, :17L, :18L, :19L, :20L, :21L, :22L, :23L)

I keep getting an error of "Parse Errors: Invalid date/time ":1" Perhaps there is a missing "," or ")". Trying to parse arguments of function "Mean"."

[#4]

It looks like JMP is having an issue correctly understanding the 1L is a column and not a numeric entry. Try changing the references to the columns to:

Mean( :Name("1L"), :Name("2L"), :Name("3L"), ….. :Name("23L") ); 

[#5 · Accepted solution]

I solved it, because of the naming of my columns I needed to put the formula as:

Mean(
	:Name( "1L" ),
	:Name( "2L" ),
	:Name( "3L" ),
	:Name( "4L" ),
	:Name( "5L" ),
	:Name( "6L" ),
	:Name( "7L" ),
	:Name( "8L" ),
	:Name( "9L" ),
	:Name( "10L" ),
	:Name( "11L" ),
	:Name( "12L" ),
	:Name( "13L" ),
	:Name( "14L" ),
	:Name( "15L" ),
	:Name( "16L" ),
	:Name( "17L" ),
	:Name( "18L" ),
	:Name( "19L" ),
	:Name( "20L" ),
	:Name( "21L" ),
	:Name( "22L" ),
	:Name( "23L" )
)

[#6]

In addition to @txnelson's suggestion, you could also use the Functional Data Explorer if you have JMP Pro. It automatically determines and plots the mean function. The function summaries can be saved and used in another plotting platform.