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Jan 11, 2019 10:30 AM
(5234 views)

What is the quickest way to convert a list: {"a", 1, 2, "b"} into a matrix: [. 1 2 .]?

I expect that I can just loop through all of the elements, but I'm hoping there is a quicker way since I will be doing this many thousands of times in my application, with each list containing hundreds of elements.

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This is pretty fast:

```
MyList = {"a", 1, 2, "b"};
Mat = Number Col Box("", MyList) << get as matrix;
```

9 REPLIES 9

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Re: Convert List to Matrix

I don't know if using a data table is ok ? if yes, here you go . Since the data table is private, I would expect it to be more than reasonably fast for hundreds of values

```
MyList = {"a", 1, 2, "b"} ;
dt = New Table("Temp",
New Column("C",Numeric,values(MyList)),
"Private"
);
Mat = dt << get as matrix;
Close(dt,"No Save");
Show(Mat);
```

Best

Uday

Uday

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Re: Convert List to Matrix

Thanks, I'll give that a try.

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Re: Convert List to Matrix

Looking at your original question, you wanted a matrix of [1,2]. I have added in a statement to get rid of the missing values

```
MyList = {"a", 1, 2, "b"} ;
dt = New Table("Temp",
New Column("C",Numeric,values(MyList)),
"Private"
);
dt << select where( ismissing(:c)) << delete rows;
Mat = dt << get as matrix;
Close(dt,"No Save");
Show(Mat);
```

Jim

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Re: Convert List to Matrix

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This is pretty fast:

```
MyList = {"a", 1, 2, "b"};
Mat = Number Col Box("", MyList) << get as matrix;
```

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Re: Convert List to Matrix

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Re: Convert List to Matrix

Not sure about memory handling here. But since the NumberColBox isn't drawn or stored in a variable I don't think it uses or locks up significant amounts of memory.

It also seems to scale linearly: If looped 10000x , 100000x and 1000000x it takes 0.27, 2.7 and 26.7 seconds, respectively. No difference in memory usage.

Applied to this small list, the number col box is about 30 times faster than the data table approach posted above. For very long lists – there may be an upper limit for how many items a NumberColBox can hold – the data table method may be more efficient.

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Re: Convert List to Matrix

To be perfect, I did this:

`data = shape(Number Col Box("", dt[1,0]) << get as matrix, 1, N Cols(dt));`

Now, given similarly constructed matrices for the LSL/USL specs, I can do:

`If( max(data < LSL) > 0 | max(data > USL) > 0, "FAIL", "PASS")`

to check a row of data against the limits specified in the column properties, without having to loop through the columns for every row.

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Re: Convert List to Matrix