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Mar 16, 2017 9:19 AM
(1779 views)

Hello,

I have a column (type formula) which corresponds to the model of another column (response).

I would like to know if it is possible to graph the actual by predicted plot considering as "actual" the response column and the column which contains the formula as the "predicted".

I only see these graph when the model is defined by jmp.

Thanks in advance.

1 ACCEPTED SOLUTION

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Mar 16, 2017 9:56 AM
(3521 views)

Solution

This could be done with column formulas but it would get messy. This script should do the trick:

```
dlg = Column Dialog(
Title( "Evaluate Model" ),
yCol = Col List( "Response",
Data Type( Numeric ),
Min Col( 1 ),
Max Col( 1 )
),
mCol = Col List( "Model",
Data Type( Numeric ),
Min Col( 1 ),
Max Col( 1 )
)
);
If( dlg["Button"] == -1,
Throw( "User cancelled" );
);
Remove From( dlg );
Eval List( dlg );
dt = Current Data Table();
response = yCol[1] << Get As Matrix;
model = mCol[1] << Get As Matrix;
residual = model - response;
sst = Sum( (response - Mean( response ) )^2 );
sse = Sum( residual^2 );
ssm = sst - sse;
r square = ssm / sst;
dt << New Column( "Residual", Values( residual ) );
New Window( "Evaluate Model",
dt << Graph Builder(
Variables( X( mCol[1] ), Y( yCol[1] ) ),
Elements( Points( X, Y, Legend( 3 ) ) ),
Show Control Panel( 0 )
),
dt << Graph Builder(
Variables( X( :Residual ), Y( yCol[1] ) ),
Elements( Points( X, Y, Legend( 3 ) ) ),
Show Control Panel( 0 )
),
Text Box( "R square is " || Char( r square ) )
);
```

Learn it once, use it forever!

4 REPLIES

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Mar 16, 2017 9:23 AM
(1776 views)

I think the solution might be simple.

- Select Graph > Graph Builder.
- Select the observed response and drag it to the Y drop zone.
- Select the model column and drag it to the X drop zone.

Let me know if I over-simplified your request.

Learn it once, use it forever!

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Mar 16, 2017 9:30 AM
(1773 views)

Hello,

Thank's for your answer. I think I did not explain very well my objective.

What I want to do, it is to evaluate my model. I would like to define the RSquare value of the model (if it is possible) and obtain the residual by predicted plot. Something like the jmp report for the fit least squares but considering the model that I defined as a formula.

Kind regards

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Mar 16, 2017 9:56 AM
(3522 views)

This could be done with column formulas but it would get messy. This script should do the trick:

```
dlg = Column Dialog(
Title( "Evaluate Model" ),
yCol = Col List( "Response",
Data Type( Numeric ),
Min Col( 1 ),
Max Col( 1 )
),
mCol = Col List( "Model",
Data Type( Numeric ),
Min Col( 1 ),
Max Col( 1 )
)
);
If( dlg["Button"] == -1,
Throw( "User cancelled" );
);
Remove From( dlg );
Eval List( dlg );
dt = Current Data Table();
response = yCol[1] << Get As Matrix;
model = mCol[1] << Get As Matrix;
residual = model - response;
sst = Sum( (response - Mean( response ) )^2 );
sse = Sum( residual^2 );
ssm = sst - sse;
r square = ssm / sst;
dt << New Column( "Residual", Values( residual ) );
New Window( "Evaluate Model",
dt << Graph Builder(
Variables( X( mCol[1] ), Y( yCol[1] ) ),
Elements( Points( X, Y, Legend( 3 ) ) ),
Show Control Panel( 0 )
),
dt << Graph Builder(
Variables( X( :Residual ), Y( yCol[1] ) ),
Elements( Points( X, Y, Legend( 3 ) ) ),
Show Control Panel( 0 )
),
Text Box( "R square is " || Char( r square ) )
);
```

Learn it once, use it forever!

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Mar 16, 2017 1:52 PM
(1760 views)

Best,

M