HI,
I want to subtract 6 hrs in 05-07-2022 01:00 so final value should be 04-07-2022 19:00Can you please suggest me how perform this calculation in JMP16.
Many thanks
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Use the In Hours() function
Date = Informat( "05/07/2022 01:00:00", "m/d/y h:m:s" ); New Date = Date - In Hours( 6 ); Show( Format( New Date, "m/d/y h:m:s" ) );
Displays
Format(New Date, "m/d/y h:m:s") = "05/06/2022 7:00:00 PM";
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