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  • JMP Security Notice: CVE-2026-109618 and CVE-2026-109619

    JMP promptly initiated a review of its products, services, and relevant infrastructure for exposure to CVE-2026-109618 and CVE-2026-109619.

    Our assessment of JMP products has not identified exposure to these vulnerabilities. Where remediation was required within supporting environments, appropriate security updates and controls have been applied and validated.

    We have identified no evidence of successful exploitation or unauthorized access to JMP systems or customer information associated with these vulnerabilities.

    JMP continues to monitor the issue and relevant vendor guidance. No action is required by JMP customers at this time.

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Discussions

Solve problems, and share tips and tricks with other JMP users.
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chfields
Level II

Is it possible to create Histograms from a list?

I have data sets where data is in Columns.  I want to create histograms for each parameter.

I know that I could stack the data and us the following command:

Current Data Table() << Distribution( Continuous Distribution( Column( :param_value ) ), By( :param_name ) );

I would like to use a list to create the histograms as I have code to work on each column individually.

I have tried the following with no luck:

::param_list = {:parameter1, :parameter2, :parameter3, :parameter4};

Current Data Table() << Distribution( Continuous Distribution( Column( ::param_list ) ));

2 REPLIES 2

Re: Is it possible to create Histograms from a list?

You could grab the data from the table as a matrix.  Take a single row of data and transpose it - giving you the list of data required by the distribution platform.

Best,

M

Kevin_Anderson
Level VI

Re: Is it possible to create Histograms from a list?

Try this (you need to evaluate the list!):

Semi_dt = Open( “$SAMPLE_DATA/Semiconductor Capability.jmp” );

cont_lst = Semi_dt << Get Column Names( Continuous );

Distribution( Column( Eval( cont_lst ) ),  Ignore Platform Preferences( 1 ), Histograms Only );

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