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lala
Level VIII

How will the row characters be matched from left to right to the last decimal point using the re?

 

 

So what's left over on the right-hand side is the non-green part of each row.

 

Thanks!

20220516212519.png

 

2 ACCEPTED SOLUTIONS

Accepted Solutions
Craige_Hales
Super User

Re: How will the row characters be matched from left to right to the last decimal point using the re?

I think you are asking for a regex to match all but the last segment.

regex("aaa.bbb.ccc.ddd","([^\.]+\.)+")

aaa.bbb.ccc.

 

[^\.] means a single character that is not a period

[^\.]+ means one or more of those characters

[^\.]+\. means match the period

([^\.]+\.)+ means do all that one or more times

Craige

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Craige_Hales
Super User

Re: How will the row characters be matched from left to right to the last decimal point using the re?

regex is not the best way to attack this problem.

 

word(-1,"aaa.bbb.ccc.this is it",".") // "this is it"

will get the last segment efficiently.

 

word([1 -2],"aaa.bbb.ccc.this is it",".") // "aaa.bbb.ccc"

will get the left part efficiently.

 

Craige

View solution in original post

3 REPLIES 3
Craige_Hales
Super User

Re: How will the row characters be matched from left to right to the last decimal point using the re?

I think you are asking for a regex to match all but the last segment.

regex("aaa.bbb.ccc.ddd","([^\.]+\.)+")

aaa.bbb.ccc.

 

[^\.] means a single character that is not a period

[^\.]+ means one or more of those characters

[^\.]+\. means match the period

([^\.]+\.)+ means do all that one or more times

Craige
lala
Level VIII

Re: How will the row characters be matched from left to right to the last decimal point using the re?

na1=Regex("aaa.bbb.ccc.ddd","[^\..]+$");
Craige_Hales
Super User

Re: How will the row characters be matched from left to right to the last decimal point using the re?

regex is not the best way to attack this problem.

 

word(-1,"aaa.bbb.ccc.this is it",".") // "this is it"

will get the last segment efficiently.

 

word([1 -2],"aaa.bbb.ccc.this is it",".") // "aaa.bbb.ccc"

will get the left part efficiently.

 

Craige