May 29, 2014
Topics: Using Fit Y by X for Chi-Square test of homogeneity and independence.
Category: Basic Inference - Proportions and Means
JMP features: Analyze > Fit Y by X.
Open One-Page Guide (PDF)
How can I test if type and marital status are independent of each other in the Chi-Square test under contingency analysis that is mentioned in one page guide. How can I consider both variables as Y? If I chose both type and marital status for Y (response), what should I chose for X (factor) to test for independence in the lunch platform? pls help.