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Thursday
(160 views)

All,

I have a specific problem to solve, and, although I succefully solved it on a tiny subset of original data manually, I won't be able to do this to the whole huge set of data.

So, here's the problem. I have two tables.

First table - some measurements done on some set of tools

Tool | Date | Measurement |

A001 | 1/1/2017 | 0.005 |

B006 | 2/2/2017 | 0.003 |

Second table - history of some parts replacement on the same tools:

Tool | Date | Part S/N |

A001 | 1/1/2016 | 1234567 |

B006 | 2/2/2016 | 0987654 |

A001 | 12/29/2016 | 1234568 |

What I would like to see, how measurements for each tool depend on the installed part age. What I need as a resultant table is the same table with measurements, only with few added columns:

Tool | Date | Measurement | Installed part | Installation date | Age of part |

A001 | 1/1/2017 | 0.005 | 1234568 | 12/29/2016 | 4 days |

B006 | 2/2/2017 | 0.003 | 0987654 | 12/29/2016 | 365 days |

Basically, I did this manually for one tool - just created column and filled it with the ear;liest replacement date. Then moved down the measurement table until the date of next install - and from there filled the same column to the end with new install date, then moved further.... Tedious.

I need to somehow automate that, but I can't even start wrapping my head around it.

So, for each line in measurement table, I need to find a line in parts replacement table, that has matched tool, and has install date earlier than the date for line under consideration. Then I would need to take that serial number, that date and put it in measurement table. Then it's easy to calculate part age. Some parts install dates are so long ago that they are not covered by both these tables, so I might have lots of missing values.

Could somebody help me with methodology and maybe a little bit with starting the script?

Thanks a lot!

7 REPLIES

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Thursday
(134 views)

Thanks!

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Thursday
(132 views)

you can insert a table by clicking on the table icon

11 | 44 | 222 |

333 | 444 | 66 |

88 | 55 | 99 |

Jim

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Thursday
(126 views)

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Friday
(115 views)

You could try something like this:

```
NamesDefaultToHere(1);
dt1 = DataTable("Measurements On Tools");
dt2 = DataTable("Parts Replaced");
// Get a list of the tools on which measurements were made
toolsUsed = Column(dt1, "Tool") << getValues;
// Get a list of the tools which had one or more parts replaced
toolsWithReplacedPart = Column(dt2, "Tool") << getValues;
// Get the corresponding replacement dates
replacedOn = Column(dt2, "Date") << getValues;
// And the corresponding part numbers
partSN = Column(dt2, "Part SN") << getValues;
// Make a new vector and a list that will be populated via the loop below
dates = J(NRow(dt1), 1, .);
parts = {};
// Loop over each measurement made
for(t=1, t<=NItems(toolsUsed), t++,
thisTool = toolsUsed[t];
// Find the rows in dt2 in which this tool is referenced
rowsForThisTool = Loc(toolsWithReplacedPart, thisTool);
// Find the latest date on which a part was replaced and store it
latestReplacementDate = Max(replacedOn[rowsForThisTool]);
dates[t] = latestReplacementDate;
// Identify the new part used and store it
rowForLatestPart = Loc(replacedOn[rowsForThisTool] == latestReplacementDate);
newPart = partSN[rowsForThisTool][rowForLatestPart];
InsertInto(parts, newPart);
);
// Add the new columns to dt1
dt1 << newColumn("Last Installed Part", Character, Values(parts));
dt1 << newColumn("Installed Date", Numeric, Continuous, Values(dates), Format( "m/d/y", 12 ));
dt1 << New Column( "Age of Part", Numeric, Continuous, Format( ":day:hr:m", 14 ), Formula( :Date - :Installed Date ));
```

The code is verbose to try to show the logic used. Bear in mind this has had no testing, and could be much improved: For example the '<<getValues()' are not needed (in JMP 13 at least).

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Friday
(82 views)

Ian,

Thanks a lot for such a detailed answer.

Quick question on this:

latestReplacementDate = Max(replacedOn[rowsForThisTool]);

Parts replacements are done regularly as measurements go. So I need not only find the latest, I need to find the part that was on the tool during that measurement, simple latest won't do. Basically, I need to find the latest replacedOn date such that the date of measurement is greater than the repplacedOn date. Any suggestion on how to do it in a most efficient and elegant way? I'm having years worth of daily data on tens of tools with parts replacements every month or so, so it better be efficient - so far I can only come up with another loop comparing dates one by one.

If you have a more elegant solution right out of your mind, I'd appreciate this very much.

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Friday
(80 views)

Ian,

Do you think something like this would work:

currentReplacementDate = Max(replacedOn[rowsForThisTool]<thisDate);

Where thisDate is analog of thisTool:

thisDate = currentMeasDate[t];

and currentMeasDate is just a date from measurement table.

Now, since these two tables are produced by different systems, dates formats are different (y/m/d vs m/d/y hh:mm:ss or something like that). Do I need to somehow translate one to another, or it'll be done automatically?

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Friday
(64 views)

Ian,

Are you sure that

Loc(replacedOn[rowsForThisTool] == latestReplacementDate);

is correct syntaxis?

I mean I get what you wanted to do here, but it gives me error and syntaxis help says that it whould be Loc(x,y) - gives you all indices in x where it is equal to y. Equal only, not any logical statement. Any ideas how to re-write this statement?

Thanks!