Folks,
What are the ways (or best way) to overlay another graph onto another as shown in first attachment? Final objective is to generate multiple plots, arrange them in a window that is saved as a table property. This table property is then run so the final composite picture is able to be copied and pasted to Powerpoint.
The script I have so far almost gets me there (see attached script and 2nd attachment). My current script obviously goes into the Report for each generated graph and a "Get Picture" command is used to populate the Lineup Box. I have tried to treat the Histogram only as an image, and do an "Add Image", but was not able to make it work.
If an Add Image command is the way to go, my additional question is to how to appropriately come up with the "bounds" arguments to position properly?
Neil
cr = Current Data Table() << Run Script("Cumulative Resistivity");
rpt_cr = Report(cr);
rpt_cr_pic = rpt_cr[PictureBox(1)] << Get Picture;
ds = Current Data Table() << Run Script("Distribution");
rpt_ds = Report(ds);
rpt_ds_pic = rpt_ds[ListBox(4)] << Get Picture;
//comb = New Image( rpt_ds_pic );
//rpt_cr_pic << Add Image( comb, bounds(left(0), top(500),bottom(0),right(724)));
nw = Eval Expr( New Window("BR",
a = V List Box(
Lineup Box(N Col(2), rpt_cr_pic, rpt_ds_pic ),
)
)
);
Current Data Table() << New Script("RP", nw) ;
Hi,
The only way I know to do this is as follows:
1) Get your images and get the matrices of pixels for them.
2) Overwrite a submatrix of the "lower" image's pixels with the pixel matrix of the "upper" image.
Below is a script illustrating this, and an image (actually a window of 3 images where the "top" image has been "pasted" in different locations) showing the results. You may have to experiment to get your image where you want it, but this approach should eventually do the trick.
names default to here(1);
//make a table
dt = astable(J(50,2,randomuniform()));
//make a graph
gb = dt << Graph Builder(
Size( 500, 500 ),
Show Control Panel( 0 ),
Variables( X( :col1 ), Y( :col2 ) ),
Elements( Points( X, Y, Legend( 5 ) ) ),
);
//save to a picture, get the pixels and get the picture's x and y dimemnsions
pic1 = (report(gb)[framebox(1)] << get picture) << get pixels;
pic1y = nrow(pic1);
pic1x = ncol(pic1);
//now make another graph and do the same
dist = dt << distribution(histograms only, y(:col1));
pic2 = (report(dist)[framebox(1)] << get picture) << get pixels;
pic2y = nrow(pic2);
pic2x = ncol(pic2);
//create a window to place the resulting images
nw = new window("xx",
vlb = vlistbox(
)
);
x = y = 1; //initial "corner" of overwritten pixels... we will increment these and do 3 total pictures
for(i = 1, i<=3, i++,
newPic = pic1;
newPic[ y::(y+pic2y-1), x::(x+pic2x-1), ] = pic2;
vlb << append(picturebox(new image(newPic)));
y += 60;
x+= 150;
);
Cheers,
Brady
Brady,
I just got something that seemed to work earlier today, but I want to take a crack at your approach as well.
Based off the "Add Image" command (and example) in the Scripting index, I was able to get the image shown below. My only issue was that the Graph Box seemed to be the only Display Element Box that allowed me to get the result. Also, X and Y axis are still present, and I'm not sure how to hide them. My code is attached.
Neil
