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4 weeks ago
(388 views)

Hi I have a table like this and what I want to do is:

--> For every row, do a +-1 to X and +-1 to Y and take median of those four Age values and save it under a new column. Can someone please help?

X Y Age

-1 2 27

2 -1 23

4 5 56

-7 -4 43

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4 weeks ago
(578 views)

Solution

Attached is a sample data table, with the 4 new columns, with their formulas, and the Median column, with it;s formula. Below is an example of the formulas I placed into the data table. This is the X-1, Y column formula

```
dt = Current Data Table();
TheRow = Row();
Xval = :X - 1;
Yval = :Y;
MyRows = dt << get rows where( :X == Xval & :Y == Yval );
If( N Rows( MyRows ) > 0,
TheResult = dt:Age[MyRows[1]]
);
```

Jim

7 REPLIES

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4 weeks ago
(379 views)

@rk1988 :

Let us assume your table is called "dt"

The following piece of code should add and subtract 1 to X and Y as new columns .

dt << New Column("AddXBias",Numeric,Continuous,Formula(:X+1)) << New Column("SubXBias",Numeric,Continuous,Formula(:X-1)) << New Column("AddYBias",Numeric,Continuous,Formula(:Y+1)) << New Column("SubYBias",Numeric,Continuous,Formula(:Y-1));

Now , the question is which columns you want to take the mean of ?

If it is just the age column , this should do it

AgeMean = Col Mean(:Age);

If it is some other values, please provide clear direction on which values and I will try to help

Best

Uday

Uday

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4 weeks ago
(373 views)

Thanks for your response :) Let me clarify...

For each row:

1. add 1 to X, now go to that row with coordinates (X+1,Y) and grab the age value --> this is variable Age1

2. subtract 1 from X, now go to that row with coordinates (X-1,Y) and grab the age value --> this is variable Age2

3. add 1 to Y, now go to that row with coordinates (X,Y+1) and grab the age value --> this is variable Age3

4. subtract 1 from Y, now go to that row with coordinates (X,Y-1) and grab the age value --> this is variable Age4

5. Calculate median of Age1...4 and save that under a new column

Repeat steps for each row...

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4 weeks ago
(366 views)

@rk1988 :

Sorry , not really following your requirement here . If you were to introduce a bias in variables "X" and "Y" as you have explained , the values in column "Age" will not be influenced. Age1 to Age4 and their mean is fixed unless the bias is introduced in Age.

And that mean can be acquired by :

Col Mean(:Age) ;

Apologies that I am unable to follow , would you like to demonstrate what you want in an excel sheet manually , so may be it is more clear .

Best

Uday

Uday

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4 weeks ago
(349 views)

I am looking for further specification. For a given case where X=3 and Y=-1, are you looking for the value of the column Age, where X=X-1, and Y is unchanged: Using your small sample table

:Age==>where(X==2 and Y==-1)==>23

Is this what you are looking for?

Jim

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4 weeks ago
(329 views)

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4 weeks ago
(579 views)

Attached is a sample data table, with the 4 new columns, with their formulas, and the Median column, with it;s formula. Below is an example of the formulas I placed into the data table. This is the X-1, Y column formula

```
dt = Current Data Table();
TheRow = Row();
Xval = :X - 1;
Yval = :Y;
MyRows = dt << get rows where( :X == Xval & :Y == Yval );
If( N Rows( MyRows ) > 0,
TheResult = dt:Age[MyRows[1]]
);
```

Jim

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4 weeks ago
(296 views)