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How to open files with a certain file name only?

Hi Guys,

I am trying to open some files which have a certain name as follows:

files1 = Files In Directory( "C:\log\*.test*" );

However I do not get anything in files1. How can I just search for specific file names and save them in the files1 list?

Thanks.
4 REPLIES
mpb

Super User

Joined:

Jun 23, 2011

One way:

files1 = Files In Directory("C:\log")

Then go through the list and discard any file names that do not match your file mask, leaving a smaller list containing only the kind of file names you want.
Is there a * wildcard that I can use? I am used to grep in unix. I am trying something as follows:

mpb

Super User

Joined:

Jun 23, 2011

Try this:
= 1, i--,
If( !Starts With( files1[i], "test" ),
Remove From( files1, i )
);
);
Show( files1 );

-->
That worked, Thanks.