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- Get the a modeled output in a use-able form?

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Feb 12, 2016 3:03 PM
(1381 views)

I have a data set that comes close to fitting neatly in a tabulate output. All of the X's are categorical. All of the Y's are continuous. There are some combinations of x's, however that have very few data points or no data points, so I get an unreliable or non-existent Y.

To solve this problem, I want to use Fit Model. I can get a very reasonably looking model

Prediction Expression

One point for example:

But I don't know how to output this efficiently. I could look at every point by hand. Or I could take the Parameter Estimates or the Prediction Expression and write a long series of if/then code. But I figure there must be something I'm missing. What I would like is an output like the tabulate I started with but with but filled in with the estimated values. Is there a way to do that in JMP or am I using the wrong tool?

Thanks.

5 REPLIES

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Feb 13, 2016 4:34 AM
(1275 views)

hi feldybikes,

Perhaps one option for you could be "Output grid table" under the red triangle of the prediction profiler.

alternatively, one of the LSmeans options can be useful. you will find them under the red triangle of the leverage plots.

best,

ron

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Feb 16, 2016 11:54 AM
(1275 views)

Thanks very much for the response. I think this is what I was looking for. Didn't think to look in the menu of the profilter.

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Feb 15, 2016 2:12 AM
(1275 views)

I'm not sure if the values in your first 'Tabulate' are predicted or actual values. In any case, though, if you want to estimate or impute missing cells in this tabulation, you could:

- Use Fit Model for the actual values you have.
- Save the prediction formula as a column back to the table.
- Build 'the same' tabulation using 2. for Y.
- Inspect the values in the cells that were previously '.'

You could use JSL to automate this if you wanted to.

But I'm not sure I have understood your question correctly.

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Feb 16, 2016 11:57 AM
(1275 views)

Always nice to have options on how to solve the problem.

There shouldn't be any difference between saving the predicted value to a column and saving the prediction formula to a column, right? The formula might just be helpful if I were using that prediction with another data set?

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Feb 16, 2016 12:09 PM
(1275 views)

Yes, that's correct - If you add a new row to the table that has the required 'x values', then the 'y value' computed by the formula will just appear in the appropriate cell automatically.