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- Formula usage: How to create second column based o...

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Nov 21, 2013 1:33 AM
(2213 views)

Hi, a recurring tasks can be seen in the attached JMP data table example. A first column has row values, that need to be continued for more rows than where the first column has the value. In thye example the first column has the numbers 1, 2, 3 etc mixed with letters (or any other irrevelant information). Now, the value of the second column should always be equal to the *last* value encountered in the first column. When a new *number* is seen in the first column, *that* value should be continued. Sounds complicated, but looks simpler in the table.

Any help appreciated. (In base SAS retain would do the job.)

Regards

Poul

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Nov 21, 2013 2:12 AM
(4130 views)

Solution

If you need a formula column, I think this will work (assumes first row in Column 1 is a number):

New Column**(** "test",

Numeric,

Continuous,

Formula**(**

If**(** Is Missing**(** Num**(** :Column 1 **)** **)**,

Lag**(** :test, **1** **)**,

Num**(** :Column 1 **)**

**)**

**)**

**)**;

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Nov 21, 2013 2:12 AM
(4131 views)

If you need a formula column, I think this will work (assumes first row in Column 1 is a number):

New Column**(** "test",

Numeric,

Continuous,

Formula**(**

If**(** Is Missing**(** Num**(** :Column 1 **)** **)**,

Lag**(** :test, **1** **)**,

Num**(** :Column 1 **)**

**)**

**)**

**)**;