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Formula in New Column Command

Jun 12, 2012 5:46 AM
(1302 views)

Hi,

I often receive data in SPSS format. When I import the data into JMP, I maintain the SPSS names. JMP creates a new column property called "SPSS Name" and also uses these names as the column names. My goal is to change the column names based on "SPSS Name", add a new column with the new column name but with an added character in the name, and then have a formula for this new column. As an example, suppose I use the Big Class table. I added a new property to each column and called it "SPSS Name". I then set each SPSS Name to "Q1", "Q2", ..., "Q5" which is along the lines of what the original SPSS file names would be like. I created the following script which looks for the SPSS Name "Q4" (which corresponds to the height column in Big Class), changes the column name to "New Height", and adds a new column called "New Height - B". This part works fine. What I can't get to work is the formula part. The new column should have a formula with a value based on the height column that was renamed; that is, based on "New Height". When I look at the new column, all I see are missing value codes. The formula property has the correct formula except that "x" is used rather than "New Height" as I would expect. How can I get this last part to work? Any suggestions?

dt = Current Data Table();

for(i = 1, i <= N Col( dt ), i++,

col = Column( i );

match( col << Get Property("SPSS NAME"),

"Q4",

x = "New Height";

col << Set Name( x );

New Column( x || " - B", Numeric, Continuous,

Width( 5 ), Formula( If( Column( x ) > 60, 1, 0 ) )

)

);

);

dt << Run Formulas;

Thanks,

Walt Paczkowski

1 REPLY 1

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Re: Formula in New Column Command

The substitute command can be a tricky one and takes a while to grasp.

I created the SPSS property of 'Q4' under the height column as you did.

dt = Current Data Table();

For(i = 1, i <= NCol(dt), i++,

col = Column(i);

Match(col << Get Property("SPSS NAME"),

"Q4",

newcoln = col << get name || " - B";

newcol = dt << NewColumn(newcoln);

// subsitute the values instead of the references

Eval(Substitute(

Expr(newcol << Set Formula(If( _xvar > 60, 1, 0))),

Expr( _xvar ), Parse(col << Get Name))

);

);

);