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Formula for automatic counter by group of rows

sornasst

Community Trekker

Joined:

Feb 2, 2016

Hi,

I would like to write a formula in JMP 11.1 that will automatically create a counter by  group of rows as shown in the table below

GroupCounter
ABC1
ABC1
ABC1
ABC1
CDE2
CDE2
EFG3
EFG3
EFG3
GHI4
GHI4
GHI4

I suspect that the Dif() and/or Lag() functions have something to do with this but I have not been able to implement it.

Note: this counter by group of rows is very easy to implement in Excel

Thank you for your help.

1 ACCEPTED SOLUTION

Accepted Solutions
Solution

Assuming the data are sorted:

If(Row() == 1, counter = 1); If(:group == Lag(:group), counter, counter = counter + 1); counter

Jim
2 REPLIES
Solution

Assuming the data are sorted:

If(Row() == 1, counter = 1); If(:group == Lag(:group), counter, counter = counter + 1); counter

Jim
Jeff_Perkinson

Community Manager

Joined:

Jun 23, 2011

Here's the formula version of Jim's answer.

If( Row() == 1,

1,

Lag( :Counter Formula, 1 ) + (Lag( :Group, 1 ) != :Group)

)

12602_JMPScreenSnapz039.png

Notice that the addition step takes advantage of the fact that comparisons result in a 1 or 0 for true or false. So, we can compare the value of Group in the current row to the previous row and if they are not equal (!=) it will add 1.

-Jeff

-Jeff